Answer:
22 2/9
Step-by-step explanation:
When z "varies jointly" with x and y, it can be described by the formula
z = kxy
Here, we have bags of mulch (n) varying jointly with area (a) and depth (d), both in feet. The given information can let us find the value of k.
n = kad
10 = k·(120)(1/4)
10/30 = k = 1/3 . . . . . divide by the coefficient of k
Now, we can fill in the other values of interest.
n = (1/3)·(200)·(1/3) = 200/9
n = 22 2/9
You need 22 2/9 bags of mulch to cover 200 ft² to a depth of 4 inches.
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<em>Comment on the problem</em>
This problem requires the formula be written with both area and depth expressed in feet, yet it gives depth in inches. The formula can also be written using depth in inches. In that case, k = 1/36.
First, tan(<em>θ</em>) = sin(<em>θ</em>) / cos(<em>θ</em>), so if cos(<em>θ</em>) = 3/5 > 0 and tan(<em>θ</em>) < 0, then it follows that sin(<em>θ</em>) < 0.
Recall the Pythagorean identity:
sin²(<em>θ</em>) + cos²(<em>θ</em>) = 1
Then
sin(<em>θ</em>) = -√(1 - cos²(<em>θ</em>)) = -4/5
and so
tan(<em>θ</em>) = (-4/5) / (3/5) = -4/3
The remaining trig ratios are just reciprocals of the ones found already:
sec(<em>θ</em>) = 1/cos(<em>θ</em>) = 5/3
csc(<em>θ</em>) = 1/sin(<em>θ</em>) = -5/4
cot(<em>θ</em>) = 1/tan(<em>θ</em>) = -3/4
Google maps
XD
This depends on what equipment you have, as I said before the internet is one way but you could use a scale map etc..
Answer:
3600 gallons of water was removed from the basement.
Step-by-step explanation:
Given:
Rate of each pump = 40 gallons/min
We need to find find the number of gallons of water removed from the basement.
Solution:
Now Given:
After half an hour, the one pump burns out.
Now we know that;
1 hour = 60 mins
hour = 
Now for 30 mins both the pumps were working and removing the water.
So we can say that;
Water remove for first 30 mins = 
Also Given:
the second pump finishes removing the water half an hour later.
So we can say that;
Water removed for next 30 mins = 
Now we can say that;
Total water removed from the basement is equal to sum of Water remove for first 30 mins and Water removed for next 30 mins .
framing in equation form we get;
Total water removed from the basement = 
Hence 3600 gallons of water was removed from the basement.
