62.85 times so basically 63 times
Answer:
A) 44.1
Step-by-step explanation:
I used omnicalculator. Should count because it's still a calculator.
Solution :
We have to prove that 
(De-Morgan's law)
Let 
then 
and 
and so 
and 
.
Thus, 
and so 
Hence, 
.........(1)
Now we will show that 
Let ⇒
Thus x is present neither in the set A nor in the set B, so by definition of the union of the sets, by definition of the complement.
and 
Therefore, 
and we have .............(2)
From (1) and (2),
Hence proved.
Answer:
15 13/5 hopefully it helps
Answer: Third option: <span>the percentage of students who earned a score of “needs improvement” on the Chapter 6 test and a score of “proficient” on the Chapter 7 test.
</span>
3 represents the number of <span>of students who earned a score of “needs improvement” on the Chapter 6 test.
16=3+13 represents the number total </span><span>of students who earned a score of “proficient” on the Chapter 7 test.
Then 3/16=0.1875=0.1875*100%=18.75% represents </span>the percentage of students who earned a score of “needs improvement” on the Chapter 6 test and a score of “proficient” on the Chapter 7 test.
