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fenix001 [56]
3 years ago
5

Find the exact values of the remaining five trigonometric functions of o satisfying the given conditions.

Mathematics
1 answer:
Lyrx [107]3 years ago
4 0

First, tan(<em>θ</em>) = sin(<em>θ</em>) / cos(<em>θ</em>), so if cos(<em>θ</em>) = 3/5 > 0 and tan(<em>θ</em>) < 0, then it follows that sin(<em>θ</em>) < 0.

Recall the Pythagorean identity:

sin²(<em>θ</em>) + cos²(<em>θ</em>) = 1

Then

sin(<em>θ</em>) = -√(1 - cos²(<em>θ</em>)) = -4/5

and so

tan(<em>θ</em>) = (-4/5) / (3/5) = -4/3

The remaining trig ratios are just reciprocals of the ones found already:

sec(<em>θ</em>) = 1/cos(<em>θ</em>) = 5/3

csc(<em>θ</em>) = 1/sin(<em>θ</em>) = -5/4

cot(<em>θ</em>) = 1/tan(<em>θ</em>) = -3/4

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For the class of 2013's prom Norman's dress shop sold cheaper dresses for $90 each and more expensive dresses for $140 each. The
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Answer:

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Step-by-step explanation:

Given:

Cost of cheaper dresses = $90

Cost of  expensive dresses = $140

Total cost of  the dresses = $5250

To Find:

Number of cheaper dress = ?

Number of expensive  dress = ?

Solution:

Let

The number of  cheaper dresses be x

The number of  expensive dresses be y

(Number of cheaper dresses X cost of cheap dress) +  (Number of Expensive dresses X cost of  expensive dress)  =  $5250

x \times90 +y \times 140 = 5250=  $5250

It is given that the 20 more of the cheaper dresses than the expensive dresses is sold

So,

number of cheaper dress  =  20  +  number of expensive dress

x = 20 + y---------------------------------------(1)

(20+y) \times90 +y \times 140 = 5250 = 5250

(20 \times 90 +y\times 90) +y \times 140= 5250

1800 + 90y+ 140y = 5250

1800 + 230y = 5250

230y =5250 -1800

230y = 3450

y = \frac{3450}{230}

y = 15

Substituting y in (1)

x = 20 +15

x= 35

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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