Answer:
The correct answer would be, $3,594,524
<span>Contemporary organizations find that wide spans create flat organizations with fewer vertical levels. Contemporary structures and forms of organizations are simple, functional structures. They are used in a simple business environment and they are traditional in their views and business practices. </span>
Answer:
Number of vats used is 3
Explanation:
Number of pounds used per hour, D = 195 ÷ 8
= 24.375 pounds per hour
Cycle time, T = 2.25
Inefficiency factor, e = 0.19
Material held in vats, C = 25 pounds
Now,
Let, n be total number of vats
Thus,
n = 
on substituting the respective values, we get
n =
or
n = 2.413 ≈ 3
Number of vats used is 3 [since vats cannot be in fraction]
<span>The difference between scarcity an shortage is that a scarcity is something that occurs naturally due to limitations on the resources that have no way to be replenished. A shortage comes from a condition in the market when a certain good is set at a certain price. So the correct answer is B.</span>
Answer:
Depreciation amount at the end of one year is $10,900
Explanation:
Land is not depreciated because land is assumed to have an unlimited useful life. Building is a long lived assest and it has limited useful lives. Therefore, building is depreciated assets.
The building acquisition cost is = Building transaction value + building transfer costs + Renovation cost
= $88,000 + $4,000 + $25,000
= $117,000
Depreciation value = The building acquisition cost - The residual value
= $117,000 - $8,000
= $109,000
Depreciation amount under the Straight-line method is calculated as below:
Yearly depreciation = 
= 
= $10,900