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Brrunno [24]
3 years ago
14

Help with 1 and 2 please!!! It's easy

Mathematics
1 answer:
s2008m [1.1K]3 years ago
4 0

1. Yes, because it can be written as a fraction.

2. No, because it cannot be written as a fraction.

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A statistician uses Chebyshev's Theorem to estimate that at least 15 % of a population lies between the values 9 and 20. Use thi
rjkz [21]

Answer:

\mu = 14.5\\

\sigma = 5.071\\

k = 1.084

Step-by-step explanation:

given that a  statistician uses Chebyshev's Theorem to estimate that at least 15 % of a population lies between the values 9 and 20.

i.e. his findings with respect to probability are

P(9

Recall Chebyshev's inequality that

P(|X-\mu |\geq k\sigma )\leq {\frac {1}{k^{2}}}\\P(|X-\mu |\leq k\sigma )\geq 1-{\frac {1}{k^{2}}}\\

Comparing with the Ii equation which is appropriate here we find that

\mu =14.5

Next what we find is

k\sigma = 5.5\\1-\frac{1}{k^2} =0.15\\\frac{1}{k^2}=0.85\\k=1.084\\1.084 (\sigma) = 5.5\\\sigma = 5.071

Thus from the given information we find that

\mu = 14.5\\\sigma = 5.071\\k = 1.084

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