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Pani-rosa [81]
3 years ago
13

Question no. e. and f. please help me !!!!!​

Mathematics
2 answers:
erastovalidia [21]3 years ago
8 0
If you need help again get that app photomath it is amazing(not sponsered)
Verizon [17]3 years ago
4 0

Answer: see proofs below

<u>Step-by-step explanation:</u>

Proofs are like a puzzle that you have to unravel.

You can manipulate the left side to get the right side (LHS → RHS)

                                                or

You can manipulate the right side to get the left side (RHS → LHS)

You will need to use Pythagorean Identities, Sum and Difference Identities, and/or Double Angle Identities when manipulating one of the sides.

Use the following Identities:

cos 2A = cos²A - sin²A

sin 2A = 2 cosA · sinA    <em>Note that A can be substituted with 2A  </em>      

sin 3A = 3 sinA - 4sin³A

cos 3A = 4cos³A - 3cosA

***********************************************************************************

e) Prove: 4 sin A · cos³A - 4 cos A · sin³A = sin(4A)

LHS → RHS

Given:         4 sin A · cos³A - 4 cos A · sin³A

Factor:        4 sin A · cos x (cos²A - sin²A)

                  2(2 sin A · cos A)(cos²A - sin²A)

Double Angle Identity:  2(sin 2·A)(cos 2·A)

                                       2 sin (2A) · cos (2A)

Double Angle Identity:  sin (2·2A)

                                       sin 4A

Proven:  sin 4A = sin 4A   \checkmark

*****************************************************************************************

f) Prove: 4 sin³A · cos 3A + 4 cos³A · sin 3A = 3 sin(4A)

LHS → RHS

Given:          4 sin³A · cos 3A + 4 cos³A · sin 3A

Triple Angle Identity:   4sin³A (4cos³A - 3 cosA) + 4cos³A (3sinA - 4sin³A)

Expand:      16sin³A · cos³A - 12sin³A · cosA + 12cos³A · sinA - 16sin³A · cos³A

Simplify:      12cos³A · sinA - 12sin³A · cosA

Expand:        6cos²A(2cosA · sinA) - 6sin²A(2cosA · sinA)

Double Angle Identity: 6cos²A(sin 2A) - 6sin²A(sin 2A)

Factor:       6sin 2A (cos²A - sin²A)

Double Angle Identity:  6sin 2A (cos 2A)

                                       3(2sin 2A · cos 2A)

Simplify:     3sin (2·2A)

                  3 sin 4A

Proven: 3sin 4A = 3sin4A   \checkmark

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Answer:

\frac{5}{4}  \times 36

5 \times 9

36

<h3>Hope this helps u... ^_^</h3>

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A line intersects the points(-22,-14) and (-18,-12). What is the slope-intercept equation for this line?
zaharov [31]

Hello there,

Well we are going to start off with the equation to find the slope based on the given points:

                                                    \frac{y_{2} - y_{1}  }{x_{2} -x_{1} }

Now using the two given points we are going to plug in and solve:

                                         \frac{(-12)-(-14)}{(-18)-(-22)} = \frac{2}{4} = \frac{1}{2}

From this you know that \frac{1}{2} is the slope of the equation. However, to find the y-intercept we are going to use y = mx+ b and plug in one of the points to solve:

                                        (-14) = \frac{1}{2} (-22) + b

                                        (-14) = (-11) + b

                                         -3 = b

That means that the y-intercept is at (0, -3). Lastly, we are just going to plug all this into the slope-intercept form:

                                       y = \frac{1}{2} - 3

Hope I helped,

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6 0
3 years ago
A field has a perimeter of 1.48 kilometers it is 460 meteres long how wide is the field
Vika [28.1K]
280 meters wide. 
Step 1: Convert kilometers to meters. 1.48=1480
Step 2: Multiply the side length that you have by 2. 2x460=920
Step 3: Subtract 920 from 1480. 1480-920=560.
Step 4: Divide 560 by 2. 560/2=280
There is your answer! 
6 0
3 years ago
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A rectangular carpet has a perimeter of 244 inches. The length of the carpet is 90 inches more than the width. Determine the dim
RSB [31]

Answer:

The dimensions of rectangle are:

Width = 16 inches

Length = 106 inches

Step-by-step explanation:

Perimeter of rectangle = 244 inches

Let Width of rectangle = w

Length of rectangle = w+90

We need to find the dimensions (length and width) of the carpet

The formula used will be: Perimeter=2(length+width)

Putting values and making equation:

244=2w+2(w+90)\\Solving:\\244=2w+2w+180\\244=4w+180\\Switching\:sides\\4w+180=244\\Subtracting\:180\:from\:both\:sides\\4w=244-180\\4w=64\\Dividing\:both\:sides\:by\:4\\\frac{4w}{4} =\frac{64}{4}\\w=16

So, we get w = 16

The width w = 16 inches

Now, finding length = w+ 90 = 16+90 = 106 inches

Therefore the dimensions of rectangle are:

Width = 16 inches

Length = 106 inches

4 0
3 years ago
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