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3 years ago

How do you do this math??

Mathematics

2 answers:

Tomtit [17]3 years ago

5 0

Answer:

y = 20 + 10x pls give me brainliest

Step-by-step explanation:

because he plans to save 10 each month so tht will increase so its 10x

and he already has 20 so thts the y intercept

Anit [1.1K]3 years ago

3 0

Answer:

y=20+10z

Step-by-step explanation:

has $20 and he has to add 10 dollars every month therefore that would be your answer

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The net profit in dollars per day for a small business owner is given by the equation f(x) = -0.1x^2 + 6 x + 4, where x is the n

notsponge [240]

Answer:

$\large \boxed{\sf \ \ \text{The maximum profit is \$94 per day.} \ \ }$

Step-by-step explanation:

Hello,

The coefficient in $x^2$ is negative.

So, there is a maximum at the vertex point which is

$x=-\dfrac{b}{2a}==\dfrac{-6}{-0.2}=\dfrac{6}{0.2}=30$

And then the maximum is f(30)=

$-0.1\cdot 30^2+6\cdot 30 +4=-90 +180+4=94$

So the maximum profit is 94 $ per day.

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

6 0

3 years ago

9 time as many as 5 is 45

Nonamiya [84]

9 times 5 equals 45 so yes

8 0

3 years ago

Read 2 more answers

John stands 150 meters from a water tower and sights the top at an angle of elevation of 36º. If John's eyes are 2 meters above

horsena [70]

Answer:

The height of tower $DB=111\ meters$ .

Step-by-step explanation:

Diagram of the given scenario is shown below.

Given that,

Distance between John and tower is $CE=150 \ meters$ .

Angle of elevation to the top of the tower is $\angle DEC=36$ °.

Height of John is $CB=2\ meters$ .

To Find: Height of the tower $DB$ .

So,

In triangle ΔDCE,

$Tan$ (∠ $DEC)= \frac{DC}{CE}$

$Tan (36)= \frac{DC}{150}$

$DC= tan(36)\times 150$

$DC=108.98\ meters$

Now,

To calculate the height of tower we have

$DB=DC+CB$

$DB=108.98+2$

$DB=110.98\ meters$ ≈ $111 \ meters$

Therefore,

The height of tower $DB=111\ meters$ .

6 0

3 years ago

Whats 2+2 User: whats 2.3 in a fraction

Sergio [31]

2 + 2 = 4.

$2.3 \times \frac{10}{10} =\boxed{\bf{\frac{23}{10} =2\frac{3}{10}}}$

5 0

3 years ago

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How much water should we add to 20 kg of seawater to change its concentration from 3% to 2%?

TiliK225 [7]

13 hope this helps !

7 0

3 years ago