You only have to check the first few, since as the factors increase, the numbers go up faster. Checking, 3 and 9 both divide 108. The answers are 3 and 9.

6 0

3 years ago

Hey, Its the same person. This is Algebra 2. Please Help!

suter [353]

Answer:

first option

Step-by-step explanation:

Given

f(x) = $\frac{2x^2+5x-12}{x+4}$ ← factorise the numerator

= $\frac{(x + 4)(2x-3)}{x+4}$ ← cancel (x + 4) on numerator/ denominator

= 2x - 3

Cancelling (x + 4) creates a discontinuity ( a hole ) at x + 4 = 0, that is

x = - 4

Substitute x = - 4 into the simplified f(x) for y- coordinate

f(- 4) = 2(- 4) - 3 = - 8 - 3 = - 11

The discontinuity occurs at (- 4, - 11 )

To obtain the zero let f(x) = 0, that is

2x - 3 = 0 ⇒ 2x = 3 ⇒ x = $\frac{3}{2}$

There is a zero at ( $\frac{3}{2}$ , 0 )

Thus

discontinuity at (- 4, - 11 ), zero at ( $\frac{3}{2}$ , 0 )

7 0

3 years ago

Three businesses donated money to charity. The chart shows the pledges made by the businesses. Business B pledged $20 million le

Masja [62]

Answer:

Business A= x

Business B= 2x-2,000,000

Business C= 2(2x-2,000,000)-2,000,000

Step-by-step explanation:

Don't feel like explaining this unless you really want me to. Also, brainliest would really be appreciated.

8 0

3 years ago

Polygons QRST and Q′R′S′T′ are shown on the following coordinate grid: A coordinate plane with two polygons is shown. Polygon QR

creativ13 [48]

As you can see from the picture you have:
to rotate point S about the origin by $90^0$ clockwise to form point S'';
to rotate point R about the origin by $90^0$ clockwise to form point R'';
to rotate point Q about the origin by $90^0$ clockwise to form point Q'';
to rotate point T about the origin by $90^0$ clockwise to form point T''.
Then you have to translate polygon Q''R''S''T'' 1 unit down.
Note that rotation $90^0$ clockwise is the same as rotation $270^0$ counterclockwise, so the correct answer is rotating $270^0$ counterclockwise about the origin and translating 1 unit down.

8 0

4 years ago

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