10. What is the equation of a line that passes through the point (4, 1) and is parallel to the line 2x - y = 42 A. y = 2x + 2 B.
1 answer:
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cosU:-
As U lies in Q3
- cosU=-24/25
sinV
As V lies in Q3
- sinV=-3/5
So
- sin(V-U)=sinVcosU-cosVsinU=(-3/5)(-24/25)-(-4/5)(-7/25)=72/125-28/125=72-28/125=<u>4</u><u>4</u><u>/</u><u>1</u><u>2</u><u>5</u>
- cos(U-V)=cosUcosV+sinUsinV=(-24/25)(-4/5)+(-7/25)(-3/5)=96/125+21/125=117/125
Answer:
Step-by-step explanation:
Since, here the length of the rectangle is represented by the function l(x) = x + 24,
While the breadth of the rectangle is represented by the function w(x) = x + 16.
And, we know that the area of the rectangle = length of the rectangle l(x) × breadth of the rectangle.
a(x) = l(x) × w(x)
a(x) = (x + 24) × (x + 16)