The patient apply pressure to his side of the tube is 15 x 10⁴ N/m². The correct option is D.
<h3>What is pressure?</h3>
The pressure is the amount of force applied per unit area. It is represented as
Pressure p = Force/Area
Given is a doctor has a patient blow on one side of a U-shaped tube that is partially filled with water and has a ball floating on the other side. The ball rises with a force of 150 N. The cross section are of the tube is 0.001 m³
The pressure applied is
p = 150 /0.001
p = 15 x 10⁴ N/m²
Hence, the patient apply pressure to his side of the tube is 15 x 10⁴ N/m².
Learn more about pressure.
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<span>THIS IS A GAS PHASE REACTION AND WE ARE GIVE PARTIAL PRESSURES . I WRITE IN TERMS OF P RATHER THAN CONCENTRATION :
lnPso2cl12=-kt+lnPso2cl1
initial partial pressure Pso2cl12 the rate constant k and the time t
lnPso2cl12=(4.5*10-2*s-1)*65*s+ln (375)
so lnPso2cl12=3.002
we take the base e antilog:
lnPso2cl12=e3.002
Pso2cl12=20 torr
we use the integrated first order rate
lnPso2cl12=3.002=k*t+ lnPso2cl12=3.002
we use the same rate constant and initial pressure
k=4.5*10-2*s-1
Pso2cl12=375
Pso2cl12=1* so2cl12
Pso2cl12=37.5 torr
subtract in Pso2cl12 grom both side
lnPso2cl12- lnPso2cl12=-kt
ln(x)-ln(y)=ln (x/y)
ln (Pso2cl12/Pso2cl20)=-kt
we get t
-1/k*ln(Pso2cl12/Pso2cl20)=t
t=51 s</span>
We can solve the problem by using the ideal gas equation:
where
p is the pressure of the gas
V is the volume of the gas
n is the number of moles of the gas
R is the gas constant
T is the absolute temperature of the gas
For the gas in our problem, we have:
If we rearrange the equation and we put these numbers into it, we find the volume of the gas:
Answer:
C
Explanation:
I am snart plus I took the same test last year
Answer:
Controlled for useful work
Explanation:
