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irina [24]
3 years ago
6

If the pressure is 100,000 Pa, R is 8.314, the temperature is 300 K, and the number of moles of gas (n) is 100, what is the volu

me in m3?
Physics
1 answer:
djyliett [7]3 years ago
4 0
We can solve the problem by using the ideal gas equation:
pV=nRT
where
p is the pressure of the gas
V is the volume of the gas
n is the number of moles of the gas
R is the gas constant
T is the absolute temperature of the gas

For the gas in our problem, we have:
p=100000 Pa
R=8.314 J mol^{-1} K^{-1}
T=300 K
n=100

If we rearrange the equation and we put these numbers into it, we find the volume of the gas:
V= \frac{nRT}{p}= \frac{(100)(8.314)(300)}{100000}=2.49 m^3
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Elena-2011 [213]

Answer:

force (tension) of 29.4 N (upward)  in 100 cm

force (tension) of 58.4 N (upward)  in 200 cm

Explanation:

Given:

Length of tube = 5 m (500 cm)

Mass of tube = 9

Suspended vertically from 150 cm and 50 cm.

Computation:

Force = Mass × gravity acceleration.

Force = 9.8 x 9

Force = 88.2 N

So,

Upward forces = Downward forces

D1 = 150 - 50 = 100 cm

D2 = 150 + 50 = 200 cm

And F1 = F2

F1 x D1 = F2 x D2

F1 x 100 = F2 x 200

F = 2F

Total force = Upward forces + Downward forces

3F = 88.2

F = 29.4 and 2F = 58.8 N

force (tension) of 29.4 N (upward)  in 100 cm

force (tension) of 58.4 N (upward)  in 200 cm

4 0
3 years ago
Part A.)Six boxes held at rest against identical walls.
krok68 [10]

Answer:

Explanation:

When a body is held against a vertical wall , to keep them in balanced position , normal force is applied on their surface . this force creates normal reaction which acts against the normal force and it is equal to the normal force as per newton's third law . Ultimately friction force is created which is proportional to normal force and it acts in vertically upward direction . It prevents the body from falling down .

Hence normal force = reaction force .

From second law also net force is zero , so if  normal force is N and reaction force is R

R - N = mass x acceleration = mass x 0 = 0

R = N .

Ranking normal force from  highest  to smallest

150 N , 130 N , 120 N

B )

Frictional force is equal to the weight of the body because the body is held at rest .

Ranking of frictional force form largest to smallest

7 kg , 5 kg , 3 kg , 1 kg .

Here frictional force is irrespective of the normal force acting on the body  because frictional force adjusts itself so that it becomes equal to weight in all cases here because it always balances the weight of the body .

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3 years ago
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zlopas [31]

Answer:

q = 3.6 10⁵  C

Explanation:

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          r = 6 , 37 106 m

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          q = E r² / k

          q = \frac{100 \ (6.37 \ 10^6)^2}{9 \ 10^9}

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Now let's calculate the charge on the planet with E = 222 N / c and radius

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When the temperature is 36 degree Celsius, we have 
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V = 331 + 21.6 = 352.6 
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3 years ago
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