Answer:
(a) 
(b) 
(c) 
(d) 
Solution:
As per the question:
Angular velocity, 
Time taken by the wheel to stop, t = 2.4 h = 
Distance from the axis, R = 38 cm = 0.38 m
Now,
(a) To calculate the constant angular velocity, suing Kinematic eqn for rotational motion:

= final angular velocity
= initial angular velocity
= angular acceleration
Now,


Now,
(b) The no. of revolutions is given by:



(c) Tangential component does not depend on instantaneous angular velocity but depends on radius and angular acceleration:

(d) The radial acceleration is given by:

Linear acceleration is given by:


Answer:
speed will double
Explanation:
Tangential velocity is given by
v=wr
where r is radius and w is rotational velocity. When r is increased to 2R, keeping roational velocity constant, the tangential velocity doubles. Hence unwinding will take place at a twice the rate and the final velocity will be double
Light can reflect from mirrors because mirrors are a prism.
Answer
given,
mass of people = 65 kg
number of people =
diameter of the merry-go-round = 4.2 m
radius = 2.1 m
angular velocity = 0.8 rad/s
moment of inertia = 1760 kg m²
Using the law of conservation of angular momentum, we have
L₁= L₂
I₁ω₁ =I₂ω₂
I₁ω₁= ( I₁+ 4 m r²)ω²
( 1760 x 0.8) = ( 1760 + 4 x 65 x 2.12)ω²
1408 = 2311.2 ω²
ω² = 0.609
ω = 0.781 rad/s
b) If the people jump of the merry-go-round radially, they exert no torque.
hence, it will not change the angular momentum of the merry-go-round. It will continue to move with the same ω .