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3 years ago

I don't know how do do these problems

Mathematics

1 answer:

zubka84 [21]3 years ago

7 0

$\bf \begin{array}{ll} term&\stackrel{a(n-1)-3}{value}\\ \cline{1-2} a(1)&-6\\ a(2)&a(2-1)-3\\ &a(1)-3\\ &-6-3\\ &-9 \blacktriangleleft\\ a(3)&a(3-1)-3\\ &a(2)-3\\ &-9-3\\ &-12 \blacktriangleleft\\ a(4)&a(4-1)-3\\ &a(3)-3\\ &-15 \blacktriangleleft\\ a(5)&a(5-1)-3\\ &a(4)-3\\ &-18 \blacktriangleleft \end{array}$

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−29,605 rounded to the nearest hundred is?

Yuki888 [10]

6 is in the hundreds place. Since the number to the right of it (0) is not greater than or equal to 5, then 6 is not rounded up.

Answer: -29,600

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3 years ago

Uber charges $0.80 per mile and a booking fee of $2.30. Lyft charges $1.07 per mile with no booking fee. Which of the systems of

gregori [183]

Answer:

Step-by-step explanation:

Let c represent the total cost of booking either Uber or Lyft for x miles.

Let m represent the number of miles ridden with either Uber or Lyft.

Uber charges $0.80 per mile and a booking fee of $2.30. This means that the total cost of riding with Uber for m miles would be

c = 2.30 + 0.8m - - - - - - - - - -1

Lyft charges $1.07 per mile with no booking fee. This means that the total cost of riding with Lyft for m miles would be

c = 1.07m - - - - - - - - - -2

Equation 1 and equation 2 are the system of equations that bests models this situation

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3 years ago

Given the function f(x)= e^3x, write an expression that represents the derivative of f using the limit shown below.

Nimfa-mama [501]

Answer:

f'(x)=6x+8

Step-by-step explanation:

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3 years ago

Approximately 0.8 of middle school students have cell phones. Which of the following fractions describes how many middle school

lana [24]

Answer: E. 4/5

Step-by-step explanation: You have to put the decimal (0.8) over its place value. So in this case 0.8 turns into 8/10. Then you must simplify 8/10, by dividing the numerator (8) and the denominator (10) by the greatest common factor (2). Which gives you the answer 4/5.

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3 years ago

Help math question derivative!

atroni [7]

Let $f(x)=\sec^{-1}x$ . Then $\sec f(x)=x$ , and differentiating both sides with respect to $x$ gives

$(\sec f(x))'=\sec f(x)\tan f(x)\,f'(x)=1$
$f'(x)=\dfrac1{\sec f(x)\tan f(x)}$

Now, when $x=\sqrt2$ , you get

$(\sec^{-1})'(\sqrt2)=f'(\sqrt2)=\dfrac1{\sec\left(\sec^{-1}\sqrt2\right)\tan\left(\sec^{-1}\sqrt2\right)}$

You have $\sec^{-1}\sqrt2=\dfrac\pi4$ , so $\sec\left(\sec^{-1}\sqrt2\right)=\sqrt2$ and $\tan\left(\sec^{-1}\sqrt2\right)=1$ . So $(\sec^{-1})'(\sqrt2)=\dfrac1{\sqrt2\times1}=\dfrac1{\sqrt2}$

5 0

3 years ago

I don't know how do do these problems​

I don't know how do do these problems