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3 years ago

16) Your salary goes from $8.75 an hour at your present job to $16.50 an hour in your new job. What is

Mathematics

1 answer:

Agata [3.3K]3 years ago

4 0

Answer:

The percent change in salary from one job to the next is 88.57%.

Step-by-step explanation:

The previous salary of per hour = $8.75 per hour

The current salary of per hour = $16.50 per hour

Change in the salary rate per hour = Current salary - Previous Salary

= $16.50 per hour - $8.75 per hour

=$7.75 per hour

⇒The change in the salary per hour rate is $7.75

Now, $\textrm{Percentage Change in salary} = \frac{\textrm{Change in the rate of salary}}{\textrm{Previous Salary}} \times 100$

= $\frac{7.75}{8.75} \times 100 = 88.57$

or, the change in salary percentage is 88.57%

Hence, the percent change in salary from one job to the next is 88.57%.

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Find the measure of an interior angle of a regular nonagon (9-sided polygon).

Scrat [10]

The measure of an interior angle of a regular nonagon (9-sided polygon) is 140°

<h3>How to determine the angle</h3>

The formula for sum of interior angles of a polygon is given as;

= ( n -2) × 180

Recall that a nonagon has nine sides, so , n = 9

Substitute the value into the formula

= ( 9 -2) × 180

= 7× 180

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Since the sum of the angles = 1260°

One of the angles = 1260/ 9 = 140°

Therefore, the measure of an interior angle of a regular nonagon (9-sided polygon) is 140°

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brainly.com/question/224658

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2 years ago

In a right triangle ΔABC, the length of leg AC = 5 ft and the hypotenuse AB = 13 ft. Find: Chapter Reference b The length of the

Butoxors [25]

Answer:

The length of the angle bisector of angle ∠A is 6.01.

Step-by-step explanation:

It is given that length of leg AC = 5 ft and the hypotenuse AB = 13 ft.

Using pythagoras theorem

$(AB)^2=(BC)^2+(AC)^2$

$(13)^2=(BC)^2+(5)^2$

$169=(BC)^2+25$

$BC=12$

$\sin A=\frac{\text{perpendicular}}{\text{hypotenuse}}$

$\sin A=\frac{BC}{AB}$

$A=\sin ^{-1}\frac{12}{13}$

$A=67.38$

Bisector divides the angle in two equal parts, therefore,

$A'=\frac{67.38}{2} =33.69$

In triangle ACD.

$\cos A'=\frac{\text{Base}}{\text{Hypotenuse}}$

$\cos A'=\frac{AC}{AD}$

$\cos (33.69^{\circ})=\frac{5}{AD}$

$0.832=\frac{5}{AD}$

$AD=\frac{5}{0.832} =6.009\approx 6.01$

Therefore the length of the angle bisector of angle ∠A is 6.01.

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3 years ago