Answer:
How long is the G2 phase = 6hours
Explanation:
Cell cycle undergoes various stages during mitotic cell division.
Normally cells are arrested in the resting phase G0 but as the cell division starts it undergoes G1 the growth phase then it undergoes S phase called the Synthesis phase in which the DNA synthesis occurs. Then it undergoes G2 Phase and is the shortest phase while G1 is the longest phase of the cycle. G2 normally lasts for 3-4 hours so here it may take 2.775 hours as due to presence of Thymidine the synthesis of DNA occur at high level so it contains higher levels of cellular DNA than in the G1 . so it will take 6hours G2 phase to occur.
Answer:
A
Explanation:
I read about ocean tides. the Moon has an effect on the ocean which causes the ocean to bulge toward the Moon. When the Moon is in alignment with the sun the ocean bulges out more because of the added gravity. The Moon though smaller than the sun has more gravitational pull than the sun.
Potassium-40 has a half life of 1.251×billion<span> years</span><span>. To determine the percentage potassium-40 remaining after 3.9 billion years, divide
3.9 by 1.251, = 3.12.
This is the number of times the original amount of potassium-40 reduces by 50%. The remaining percentage is therefore 100%/(3.12 * 2) = 16.03%.</span>
Answer:
So that oxidation of pyruvate can take place in mitochondria.
Explanation:
Pyruvates is produced in the glycolysis process which occurs in the cytoplasm. So pyruvate is produced in the cytoplasm of the cell. Pyruvate is produced by partial oxidation of glucose and to be fully oxidized it has to enter in the mitochondria.
So after entering the mitochondria the pyruvate first converts into acetyl CoA than this acetyl CoA enters in the citric acid cycle and fully oxidized into CO2. This oxidation generated NADP and FADH2 which provide reducing power during oxidative phosphorylation.
- Increased due to being able to eat larger seeds
- False
- True
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