we are given
differential equation as

we are given

Firstly, we will find y' , y'' and y'''
those are first , second and third derivative
First derivative is

Second derivative is


Third derivative is


now, we can plug these values into differential equation
and we get

now, we can factor out common terms

we can move that term on right side

now, we can factor out


now, we can set them equal





so, we will get
...............Answer
I think the answer is the third one
tenth place: 18.2
hundredth place: 18.19
one place: 18
tens place: 20
hundred place: 0
I didn't know which one you needed so I did a bunch
Answer:
2x^2 – 5x – 3
Step-by-step explanation:
<u>Apply FOIL method: </u>
=x*2x+x*1+(-3)*2x+(-3)*1
<u>Apply minus-plus rules:</u>
=2xx+1*x-3*2x-3*1
Simplify:
=2x^2 – 5x – 3
Your Answer Is 2x^2 – 5x – 3
plz mark me as brainliest :)