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Gnoma [55]
3 years ago
11

Which of these characteristics do a rhombus and a rectangle always have in common

Mathematics
2 answers:
Orlov [11]3 years ago
4 0

Answer:

A rhombus and a rectangle are both paralellograms and both have 4 sides.

Step-by-step explanation:

Imageine a rhombus as a rectangle that you have partally squished. It is still a parallellogram, and it still has four sides, it's just not 90 degree angles anymore.

earnstyle [38]3 years ago
3 0

Answer:

they are both quadrilaterals and have 4 vertices

Step-by-step explanation:


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The measure of angle PQR when Zubin drew a circle with right triangle will be 65°.

<h3>How to find the measure of the angle?</h3>

From the information given, when Zubin drew a circle with right triangle, arc QR measures 50 degrees.

Therefore, the measure of angle PQR will be:

= 180° - 90° - (1/2 × 50°)

= 180° - 90° - 25°

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A dozen apples cost$4.92 for a dozen apples is a ratio of what per Apple
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12 : 4.92

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3 years ago
Consider the expression 2√3 cos(x)csc(x)+4cos(x)-3csc(x)-2 √ 3 This expression can be represented as the product of the factors.
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Answer with explanation:

The given expression is:

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  \cos x=\frac{\sqrt{3}}{2} \wedge \csc x=\frac{-2}{\sqrt{3}}\\\\x=\frac{\pi}{6},2\pi-\frac{\pi}{6}\\\\x=\frac{\pi}{6},\frac{11\pi}{6} \wedge x=\pi+\frac{\pi}{3} ,2\pi-\frac{\pi}{3}\\\\x=\frac{4\pi}{3},\frac{5\pi}{3}\\\\x={\frac{\pi}{6},\frac{11\pi}{6},\frac{4\pi}{3},\frac{5\pi}{3}}

Option C

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3 years ago
If you have $10, and you money doubles every year, how much money will you have in 10 years?
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Year 1: 10

Year 2: 20

Year 3: 40

Year 4: 80

Year 6: 160

Year 7: 320

Year 8:  640

Year 9:  1280

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8 0
3 years ago
Read 2 more answers
Tickets to a concert cost $2 for children, $3 for teenagers and $5 for adults. When 570 people attended the concert, the total t
-Dominant- [34]

Let

x--------> the number of children

y------> the number of teenagers

z------> the number of adults

we know that

2x+3y+5z=1,950 ------> equation A

x+y+z=570 -----> equation B

y=\frac{3}{4}x

x=\frac{4}{3}y -------> equation C

Substitute equation C in equation A and equation B

2[\frac{4}{3}y]+3y+5z=1,950

\frac{17}{3}y+5z=1,950 --------> equation D

[\frac{4}{3}y]+y+z=570

\frac{7}{3}y+z=570 --------> equation E

Multiply equation E by -5

-\frac{35}{3}y-5z=-2,850 --------> equation F

Adds equation D and equation F

\frac{17}{3}y+5z=1,950\\\\-\frac{35}{3}y-5z=-2,850\\\\---------\\\\-\frac{18}{3}y=-900\\\\y=3*900/18\\\\y=150\ teenagers

therefore

<u>the answer is the option</u>

150\ teenagers


4 0
3 years ago
Read 2 more answers
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