Determining Sine and Cosine Values
1 answer:
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2(x) - [12 + 2y) ➡ 0
2(x - y - 6)
2 ➡0 {It doesn't have any solution for the equation}
x - y - 6 ➡0
y ➡ 6 over -1 ; x ➡6 over 1
The slope = 1
Therefore your answer would have to be ➡
y= 6 over -1 ; x = 6 over 1 ; slope = 1
2(x - y - 6)
2 ➡0 {It doesn't have any solution for the equation}
x - y - 6 ➡0
y ➡ 6 over -1 ; x ➡6 over 1
The slope = 1
Therefore your answer would have to be ➡
y= 6 over -1 ; x = 6 over 1 ; slope = 1