Answer:
Covalent bonds
Explanation:
A water molecule consists of two atoms of hydrogen linked by covalent bonds to the same atom of oxygen. Atoms of oxygen are electronegative and attract the shared electrons in their covalent bonds.
Answer:
An -ite or -ate ending means a polyatomic ion that includes oxygen is in the formula.
ate = one more O than -ite
Explanation:
Example:
NO2 is nitrite
NO3 is nitrate
You can see that the molecules are made of the same elements, however they have more or less of one of the elements (i.e. oxygen).
Answer:
The answer to your question is the original dose of Ba-142 was 1184 μg
Explanation:
Data
Total time = 1.25 hours
The Final amount of Ba = 9.25 μg
The Half-life of Ba = 10.6 minutes
Process
1.- Convert total time to minutes
1 h ----------------- 60 min
1.25 h ------------ x
x = 75 min
2.- Draw a table of this process
Final amount of Ba Time
9.25 75 min
18.5 64.4 min
37 53.8 min
74 43.2 min
148 32.6 min
296 22 min
592 11.4 min
1184 0.8 min
Answer:
NaOH is the limiting reactant.
204.9 g of sodium phosphate are formed.
51.94 g of excess reactant will remain.
Explanation:
The reaction that takes place is:
- H₃PO₄ + 3NaOH → Na₃PO₄ + 3H₂O
First we <u>convert the mass of both reactants to moles</u>, using their <em>respective molar masses</em>:
- H₃PO₄ ⇒ 175 g ÷ 98 g/mol = 1.78 mol
- NaOH ⇒ 150 g ÷ 40 g/mol = 3.75 mol
1.78 moles of H₃PO₄ would react completely with (1.78 * 3) 5.34 moles of NaOH. There are not as many NaOH moles so NaOH is the limiting reactant.
--
We <u>calculate the produced moles of Na₃PO₄</u> using the <em>limiting reactant</em>:
- 3.75 mol NaOH *
= 1.25 mol Na₃PO₄
Then we <u>convert moles into grams</u>:
- 1.25 mol Na₃PO₄ * 163.94 g/mol = 204.9 g
--
We calculate how many H₃PO₄ moles would react with 3.75 NaOH moles:
- 3.75 mol NaOH *
= 1.25 mol H₃PO₄
We substract that amount from the original amount:
- 1.78 - 1.25 = 0.53 mol H₃PO₄
Finally we <u>convert those remaining moles to grams</u>:
- 0.53 mol H₃PO₄ * 98 g/mol = 51.94 g