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MrRa [10]
3 years ago
14

I need help i dont understand what's it asking me to do ​

Mathematics
1 answer:
arlik [135]3 years ago
6 0

You have to prove that 2 angles are conguent to the other triangles angles; example: ∠A≅∠C by the additon POC (2 of those) and then one side; example: AB≅BA by the reflexive POE (1 of those)

I cant see the triangles but thats how you do them, also im learning this right now too, look up the triangle congruence things like ASA ≅ SSS≅ HL≅ exc. a chart will explain how to prove them using that:

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Solve using substitution:<br> y = 22x + 10<br> y = 20x + 16
stealth61 [152]

Answer:

x=3, y=76

Step-by-step explanation:

You set them equal because you plug in "y" as 22x+10 into "y=20x+16"

22x+10=20x+16

2x=6

x=3

20(3)+16=76

4 0
3 years ago
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The difference between 3 times a number x and 2 is 19. What is the value of x?
Ber [7]

Answer:

the value of x is 7.

Step-by-step explanation:

2+19=21

21÷3=7

Check:

3×7=21

21-2=19

Therefore, 7 is the answer.

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3 years ago
What is the G.C.F of 36 and 18? *
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You use 66 gallons of water on 2020 plants in your garden. At that rate, how much water will it take to water 3030 plants?
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Find the point P on the line y=2x that is closest to the point (20,0) .what is the least distance between pans (20,0)?
Vsevolod [243]
The closest point on a line, to another point, will be a point that's on a normal of that line, or a line that is perpendicular to it, notice picture below

so, y = 2x, has a slope of 2, a perpendicular line to it, will have a slope of negative reciprocal that, or \bf 2\qquad negative\implies -2\qquad reciprocal\implies \cfrac{1}{-2}\implies -\cfrac{1}{2}

so, we know that line passes through the point 20,0, and has a slope of -1/2

if we plug that in the point-slope form, we get \bf y-0=-\cfrac{1}{2}(x-20)\implies y=-\cfrac{1}{2}x+10

now, the point that's on 2x and is also on that perpendicular line, is the closest to 20,0 from 2x, thus, is where both graphs intersect, as you can see in the graph

thus  \bf 2x=-\cfrac{1}{2}x+10  solve for "x'

------------------------------------------------------------

not sure on the 2nd part, but sounds like, what's the distance from that point to 20,0, well, if that's the case, just use the distance equation

\bf \textit{distance between 2 points}\\ \quad \\&#10;\begin{array}{lllll}&#10;&x_1&y_1&x_2&y_2\\&#10;%  (a,b)&#10;&({{ \square }}\quad ,&{{ \square }})\quad &#10;%  (c,d)&#10;&({{ \square }}\quad ,&{{ \square }})&#10;\end{array}\qquad &#10;%  distance value&#10;d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}


6 0
3 years ago
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