Answer: 0.0170
Step-by-step explanation:
Given : The mean amount purchased by a typical customer at Churchill’s Grocery Store is $23.50, with a standard deviation of $5.00. 
i.e. 

We assume the distribution of amounts purchased follows the normal distribution.
Sample size : n=50
Let  be the sample mean.
 be the sample mean.
Formula : 
Then, the probability that the sample mean is at least $25.00 will be :-

Hence, the likelihood the sample mean is at least $25.00= 0.0170
 
        
             
        
        
        
Hello,
Step-by-step explanation:
90 = 9 x 10 = (7 + 2) x 10 = 70 + 20
70 men and 20 women

56 = 20 + X ⇔ X = 36
Answer : + 36 women
 
        
             
        
        
        
Answer:
5
Step-by-step explanation: