The line segment joining the points A(2,1) and B(5,-8) is trisected at the points p and q such that p is nearer to A. If p also
lies on the line given by 2x-y+k=0, find the value of k
2 answers:
Answer:
Step-by-step explanation:
2x-y+k=0 k=?
2*2-1+k=0
4-1+k=0
3+k=0
k=-3
2x-y+k=0
2*5-(-8)+k=0
10+8+k=0
18+k=0
k=-18
Answer:
k = -8
Step-by-step explanation:
The location of P is ...
P = (2A+B)/3 = (2·2+5, 2·1-8)/3 = (3, -2)
Putting this point into the equation for the line, we have ...
2(3) -(-2) +k = 0
8 +k = 0
k = -8
You might be interested in
11.333333 (three repeated, don't know how to type that
27 miles per hour 29 miles per hour and 32 miles per hour
We can re-group them to add more easily.
300 + 400 = 700
42 + 16 = 58
700+58 = 758
Answer: 758
Answer:
your answer will be 5
Step-by-step explanation:
hope it helps have a nice day/night ^_^
bye
Answer:
she needs to sell at least 44 cookies to make a $0.10 profit
Step-by-step explanation:
to find the answer all you have to do is divide 15.30 by 0.35
