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3 years ago

Help help help help help help please

Mathematics

2 answers:

ololo11 [35]3 years ago

5 0

Hello there :)

The first option: a^m-n

This is the rule quotient of powers

Good luck, u r amazing

joja [24]3 years ago

3 0

${a}^{m} \div {a}^{n} = {a}^{m - n}$

<h3>Explanation :</h3>

${a}^{m} \div {a}^{n} = {a}^{m - n}$

${a}^{m} \times {a}^{n} = {a}^{m + n}$

$( {a}^{m}){}^{n} = {a}^{m \times n}$

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Simplify 10(2x + 3) - 20.

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Answer:

Step-by-step explanation:

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3 years ago

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30% of the employees at a company picnic ate a hot dog for lunch. If 18 employees ate a hotdog, how many people were at the picn

Maksim231197 [3]

There were 60 people at the picnic.
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A job can be done by 30 men in 15 days. How long would it take 10 men to do the same job?

Vladimir79 [104]

Answer:

5 days

Step-by-step explanation:

This questions involves ratios, the job with 30 men can be done in 15 days, so the ratio from amount of men to amount of days the job will take to complete, it is 30:15. If we had 10 men instead of 30, 10 is one-third of 30, so you have to divide by 3 on each side of the ratio to get your answer.

If we do that we get the ratio 10:5.

Meaning that the 5 is the amount of days needed to be taken in order the complete the job.

Hope this helps!

3 0

3 years ago

Suppose a NBA basketball player has 5% chance of picking up a foul every minute he plays. What is the probability that he will p

alukav5142 [94]

Answer:

He wont foul out with probability 0.9093

Step-by-step explanation:

The total number of fools he picked is a Binomial ditribution noted by X with parameters p = 0.05 and N = 48. The mean of this random variable is μ = np = 48*0.05 = 2.4 and the variance is σ² = np(1-p) = 2.4*0.95 = 2.28, hence its standard deviation is σ = √2.28 = 1.51.

Note that, if approximate probability is asked, we could just approximate X with a Normal random variable with mean 2.4 and standard deviation 1.51 (this can be done because of the central limit theorem). We will calculate the probability manually. He wont foul out if he picks 0,1,2,3 or 4 fouls, thus

$P(X \leq 4) = P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4) \\= 0.95^{48}+48*0.95^{47}*0.05+{48 \choose 2}*0.95^{46}*0.05^2+\\{48 \choose 3}*0.95^{45}*0.05^3+{48 \choose 4}*0.95^{44}*0.05^4 \\= 0.085+0.215+0.266+0.215+0.127 = 0.9093$

As a consecuence, he wont foul out with probability 0.9093.

8 0

3 years ago

Use the continuous compound interest formula to find the indicated value. A=90,000; P=65,452; r=9.1%; t=? t=years (Do not round

Inga [223]

Using continuous compounding, we have:
90000=65452 x e^.091t
1.3750534743017784024934303000672=e^.091t
ln 1.3750534743017784024934303000672=ln e^.091t=.091t ln e=0.091t
t=3.5 years

3 0

3 years ago

Help help help help help help please​

Help help help help help help please