Answer:
okay, y=(1)/(2)*\sin (x-(\pi )/(4))
Step-by-step explanation:
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The numbers DO differ by 10 if they are
- 1 and 11
- 2 and 12
- 3 and 13
- 4 and 14
- 5 and 15
Each outcome technically has two ways of occurring, but since we're taking two marbles at a time, that would be the same as saying, for instance, that drawing 1 and 11 is the same as drawing 11 and 1. We only count such an event once.
So the answer is (a) 5.
Answer:
3:4.
Step-by-step explanation:
To work this out we need to find the highest multiple of 45 and 60.
15 is the largest number that goes into both of them so what we are going to do now is divide both number by 15.
45 divided by 15 = 3
60 divided by 15 = 4
Therefore the odds of selecting a red candy is 3:4.
Hope that helps. x
Hello from MrBillDoesMath!
Answer:
33
Discussion:
2 tens = 2 * 10 = 20
13 ones = 13 * 1 13
=> 2 tens + 13 ones = 20 + 13 = 33
Thank you,
MrB
Answer=7:13
Kenny's Weight*6/7=Melvin's Weight
So, for example, if Melvin's weigh was 7...
Kenny's Weight*6/7=7
divide both sides by 6/7
Kenny Weight=6
So we can say that Melvin's weight to Kenny's weight is 7:6
The boys total weights would be...
7+6=13
So Melvin's weight over the total weight of the two boys is:
7:13
