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2 years ago

Help help help help help help please

Mathematics

2 answers:

ololo11 [35]2 years ago

5 0

Hello there :)

The first option: a^m-n

This is the rule quotient of powers

Good luck, u r amazing

joja [24]2 years ago

3 0

${a}^{m} \div {a}^{n} = {a}^{m - n}$

<h3>Explanation :</h3>

${a}^{m} \div {a}^{n} = {a}^{m - n}$

${a}^{m} \times {a}^{n} = {a}^{m + n}$

$( {a}^{m}){}^{n} = {a}^{m \times n}$

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"Three times a number increased by eleven is seventeen" translates to which of the following equations?

ololo11 [35]

3x + 11 = 17 i think

7 0

3 years ago

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Do you guys the answer for number 3

ohaa [14]

Answer:

the answer is L. or the last answer

Step-by-step explanation:

you have to find the total area of the place first...

which is 21*17=357

then subtract the inner area (white area) which is

14*20=280

do 357-280 to get the remaining area and the answer is 77ft^2

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3 years ago

Please help me with this equation, add process too. Thanks

ICE Princess25 [194]

$\qquad\qquad\huge\underline{\boxed{\sf Answer☂}}$

Let's solve ~ ☂

$\qquad \sf \dashrightarrow \: - 0.6(m + 1) = 3$

$\qquad \sf \dashrightarrow \: - (m + 1) = 3 \div 0.6$

$\qquad \sf \dashrightarrow \: - (m + 1) = 5$

$\qquad \sf \dashrightarrow \: - m - 1= 5$

$\qquad \sf \dashrightarrow \: - m = 5 + 1$

$\qquad \sf \dashrightarrow \: - m = 6$

$\qquad \sf \dashrightarrow \: m = - 6$

I hope it helps ~

6 0

2 years ago

Which repeating decimal is equal in value to the fraction below? 8/9

amm1812

Can be achieved by dividing.
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8 ÷ 9 = 0.8888

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3 years ago

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Find all solutions of each equation on the interval 0 ≤ x < 2π.

Korvikt [17]

Answer:

$x = 0$ or $x = \pi$ .

Step-by-step explanation:

How are tangents and secants related to sines and cosines?

$\displaystyle \tan{x} = \frac{\sin{x}}{\cos{x}}$ .

$\displaystyle \sec{x} = \frac{1}{\cos{x}}$ .

Sticking to either cosine or sine might help simplify the calculation. By the Pythagorean Theorem, $\sin^{2}{x} = 1 - \cos^{2}{x}$ . Therefore, for the square of tangents,

$\displaystyle \tan^{2}{x} = \frac{\sin^{2}{x}}{\cos^{2}{x}} = \frac{1 - \cos^{2}{x}}{\cos^{2}{x}}$ .

This equation will thus become:

$\displaystyle \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} \cdot \frac{1}{\cos^{2}{x}} + \frac{2}{\cos^{2}{x}} - \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} = 2$ .

To simplify the calculations, replace all $\cos^{2}{x}$ with another variable. For example, let $u = \cos^{2}{x}$ . Keep in mind that $0 \le \cos^{2}{x} \le 1 \implies 0 \le u \le 1$ .