3x^2y^3+5x^3y^3-6+x^3y^2-2
= (3x^2y^3+5x^3y^3+x^3y^2)-(6+2)
= x^2y^2(3y+5xy+x)-8.
The final answer is x^2y^2(3y+5xy+x)-8~
7x-4y+24=0
i’m adding this text bc it has to be at least 20 characters so
Answer:
50
Step-by-step explanation:
2x25=50-5=45
Answer:
x=2
Step-by-step explanation:
Answer:3
Step-by-step explanation: 60/6=10
66/6=11
60/3=20
66/3=22 you double the numbers of the quotient which halves the factor.
