Answer:
yes, if AB ≅ DE
Step-by-step explanation:
Triangles are said to be congruent if they have the same sides and the same angles.
The following measures are used to determine if triangles are congruent:
1) Angle-side-angle: If two angles and a side of a triangle is equal to two angles and corresponding side of another triangle, then they are congruent.
2) Side-side-side: If all three sides of a triangle is equal to three sides of another triangle, then the two triangles are congruent.
3) Side angle side: If two sides and an included angle of a triangle is equal to the two sides and corresponding angle of another triangle, then they are congruent.
4) Hypotenuse - leg: If the hypotenuse and one leg of a triangle is equal to the hypotenuse and leg of another triangle then they are congruent.
From the triangles DEF and ABC, already, they already have one equal triangle that is ∠F = ∠B and an equal side i.e DF = AC.
To satisfy congruence, two sides and an angle have to be equal, therefore if AB = DE then the two triangles would be congruent
Answer:
the best answer i would say is D
Step-by-step explanation:
Answer:
387420489
Step-by-step explanation:
Answer:
19 678932
Step-by-step explanation:
i am not sure
Answer:
y = -1/3x + 2
Step-by-step explanation:
First, find the slope using rise over run: (y2 - y1) / (x2 - x1)
Plug in the points:
(y2 - y1) / (x2 - x1)
(3 - 5) / (-3 + 9)
-2 / 6
= -1/3
Plug in a given point and the slope into y = mx + b, and solve for b:
y = mx + b
3 = -1/3(-3) + b
3 = 1 + b
2 = b
Plug in the slope and y intercept into y = mx + b
y = -1/3x + 2
So, the equation is y = -1/3x + 2
