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aivan3 [116]
3 years ago
7

Polynomial Warm Up

Mathematics
1 answer:
Kazeer [188]3 years ago
8 0

Answer:

Step-by-step explanation:

False you must multiply the coefficient (numbers) and add the exponents.

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Which of the binomials below is a factor of this trinomial?
FromTheMoon [43]

Answer:

6 X2 6X-72

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Department stores customer parking lot has four rows with an equal number of parking spots in each row. The loud also has 15 par
Katen [24]

Answer:

4c + 15

Step-by-step explanation:

THIS IS THE COMPLETE QUESTION BELOW;

A department store's customer parking lot has 4 rows with an equal number of parking spots in each row. The lot also has 15 parking spots for store employees. If c cars can be parked in each of the 4 main rows of the parking lot, what is the expression for the maximum number of cars that can be parked in the parking lot?

15c − 4

c(15 − 4)

4c + 15

4(c + 15)

✓We were told that the customer stores parking has Total number of 4 rows,

✓ for " c" cars to be parked in the 4 main rows i.e in each of them, we can calculate the overall numbers of car parked in the rolls as ( 4 × c)= 4c

✓ we were told that there are 15 parking spots available to employees in the store

✓ maximum number of cars that can fit into the parking lot will be ( 15 + 4c)

= 4c + 15

3 0
2 years ago
Solve the equation √x+9 - 9 = -4 show each step of your solution process
Serjik [45]

Answer:

16

Step-by-step explanation:

Start by adding 9 to both sides, obtaining:  √(x + 9) = 5.

Square both sides, obtaining:   x + 9 = 25.

Subtract 9 from both sides:  x = 16

Note that √(16+9) - 9 = -4, as required.


3 0
2 years ago
Suppose small aircraft arrive at a certain airport according to a Poisson process with rate a 5 8 per hour, so that the number o
timurjin [86]

Answer:

(a) P (X = 6) = 0.12214, P (X ≥ 6) = 0.8088, P (X ≥ 10) = 0.2834.

(b) The expected value of the number of small aircraft that arrive during a 90-min period is 12 and standard deviation is 3.464.

(c) P (X ≥ 20) = 0.5298 and P (X ≤ 10) = 0.0108.

Step-by-step explanation:

Let the random variable <em>X</em> = number of aircraft arrive at a certain airport during 1-hour period.

The arrival rate is, <em>λ</em>t = 8 per hour.

(a)

For <em>t</em> = 1 the average number of aircraft arrival is:

\lambda t=8\times 1=8

The probability distribution of a Poisson distribution is:

P(X=x)=\frac{e^{-8}(8)^{x}}{x!}

Compute the value of P (X = 6) as follows:

P(X=6)=\frac{e^{-8}(8)^{6}}{6!}\\=\frac{0.00034\times262144}{720}\\ =0.12214

Thus, the probability that exactly 6 small aircraft arrive during a 1-hour period is 0.12214.

Compute the value of P (X ≥ 6) as follows:

P(X\geq 6)=1-P(X

Thus, the probability that at least 6 small aircraft arrive during a 1-hour period is 0.8088.

Compute the value of P (X ≥ 10) as follows:

P(X\geq 10)=1-P(X

Thus, the probability that at least 10 small aircraft arrive during a 1-hour period is 0.2834.

(b)

For <em>t</em> = 90 minutes = 1.5 hour, the value of <em>λ</em>, the average number of aircraft arrival is:

\lambda t=8\times 1.5=12

The expected value of the number of small aircraft that arrive during a 90-min period is 12.

The standard deviation is:

SD=\sqrt{\lambda t}=\sqrt{12}=3.464

The standard deviation of the number of small aircraft that arrive during a 90-min period is 3.464.

(c)

For <em>t</em> = 2.5 the value of <em>λ</em>, the average number of aircraft arrival is:

\lambda t=8\times 2.5=20

Compute the value of P (X ≥ 20) as follows:

P(X\geq 20)=1-P(X

Thus, the probability that at least 20 small aircraft arrive during a 2.5-hour period is 0.5298.

Compute the value of P (X ≤ 10) as follows:

P(X\leq 10)=\sum\limits^{10}_{x=0}(\frac{e^{-20}(20)^{x}}{x!})\\=0.01081\\\approx0.0108

Thus, the probability that at most 10 small aircraft arrive during a 2.5-hour period is 0.0108.

8 0
3 years ago
How to simplify 5 to the power of 0​
Dennis_Churaev [7]

Answer:

1

Step-by-step explanation:

Any positive integer to power of 0 will ALWAYS be 1.

7 0
3 years ago
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