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3 years ago

11

Jose has 7 used stamps for every 4 new stamps. If he has 28 new stamps, how many used stamps does he have?

1 answer:

kipiarov [429]3 years ago

8 0

Answer:

21

Step-by-step explanation:

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pishuonlain [190]

There is no rectangle shown.

To find area, you multiply the rectangle’s length by its width. If it comes out to be a decimal and you need to round it by the nearest tenth, then you round it to the right of the decimal point.

Ex: 2.34 -> 2.3

Then, to find how much square inches are equal to square ft, you divide the square inches by 12, I believe.

8 0

3 years ago

Whats the pattern 5,10, 30, 60, 180, ?

jonny [76]

Double the number then triple that number

4 0

3 years ago

What is the inverse of the function f(x) = 2x – 10?

Nadusha1986 [10]

Answer:

f⁻¹(x) = (1/2)x +5

Step-by-step explanation:

In y = f(x), swap the variables, then solve for y. The expression you get is f⁻¹(x).

... y = 2x -10

... x = 2y -10 . . . . . . swapped variables

... x +10 = 2y . . . . . add 10

... (1/2)x + 5 = y . . . . divide by 2

... f⁻¹(x) = (1/2)x + 5 . . . . . . rewrite using function notation

6 0

3 years ago

PLEASE ANSWERRRR!!!!!!!!

kow [346]

Answer:

you do 12 times 3 which equals 36 so 36 is your answer

7 0

2 years ago

Read 2 more answers

A rectangle is inscribed with its base on the x-axis and its upper corners on the parabola y=2−x2. What are the dimensions of su

Paul [167]

Answer:

Step-by-step explanation:

Given that a rectangle is inscribed with its base on the x-axis and its upper corners on the parabola

$y=2-x^2$

the parabola is open down with vertex at (0,2)

We can find that the rectangle also will be symmetrical about y axis.

Let the vertices on x axis by (p,0) and (-p,0)

Then other two vertices would be (p,2-p^2) (-p,2-p^2) because the vertices lie on the parabola and satisfy the parabola equation

Now width = $2-p^2$

Area = l*w = $2(2p-p^3)$

Use derivative test

I derivative = $2(2-3p^2)$

II derivative = $-12p$

Equate I derivative to 0 and consider positive value only since we want maximum

p = $\sqrt{\frac{2}{3} }$

Thus width= $\sqrt{\frac{2}{3} }$

Length = $2\sqrt{\frac{2}{3} }$

Width = $2-2/3 = 4/3$

3 0

3 years ago