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2 years ago

I will mark u brainles if you're correct

Mathematics

1 answer:

Virty [35]2 years ago

6 0

9514 1404 393

Answer:

rules of exponents apply

Step-by-step explanation:

The applicable rules of exponents are ...

a^-b = 1/a^b

(a^b)(a^c) = a^(b+c)

Applying those rules to the given equation, you get ...

$\left(\dfrac{1}{5}\right)^4\cdot\left(\dfrac{1}{5}\right)^2=5^{-6}\\\\ \left(\dfrac{1}{5^4}\right)\cdot\left(\dfrac{1}{5^2}\right)=5^{-6}\\\\ (5^{-4})(5^{-2})=5^{-6}\\\\5^{-4-2}=5^{-6}\\\\5^{-6}=5^{-6}$

You might be interested in

Past records indicate that the probability of online retail orders

Tcecarenko [31]

Answer:

a) Mean = 1.6, standard deviation = 1.21

b) 18.87% probability that zero online retail orders will turn out to be fraudulent.

c) 32.82% probability that one online retail order will turn out to be fraudulent.

d) 48.31% probability that two or more online retail orders will turn out to be fraudulent.

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The mean of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

In this problem, we have that:

$p = 0.08, n = 20$

a. What are the mean and standard deviation of the number of online retail orders that turn out to be fraudulent?

Mean

$E(X) = np = 20*0.08 = 1.6$

Standard deviation

$\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{20*0.08*0.92} = 1.21$

b. What is the probability that zero online retail orders will turn out to be fraudulent?

This is P(X = 0).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{20,0}.(0.08)^{0}.(0.92)^{20} = 0.1887$

18.87% probability that zero online retail orders will turn out to be fraudulent.

c. What is the probability that one online retail order will turn out to be fraudulent?

This is P(X = 1).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{20,1}.(0.08)^{1}.(0.92)^{19} = 0.3282$

32.82% probability that one online retail order will turn out to be fraudulent.

d. What is the probability that two or more online retail orders will turn out to be fraudulent?

Either one or less is fraudulent, or two or more are. The sum of the probabilities of these events is decimal 1. So

$P(X \leq 1) + P(X \geq 2) = 1$

We want $P(X \geq 2)$

$P(X \geq 2) = 1 - P(X \leq 1)$

In which

$P(X \leq 1) = P(X = 0) + P(X = 1)$

From itens b and c

$P(X \leq 1) = 0.1887 + 0.3282 = 0.5169$

$P(X \geq 2) = 1 - P(X \leq 1) = 1 - 0.5169 = 0.4831$

48.31% probability that two or more online retail orders will turn out to be fraudulent.

4 0

3 years ago

Solve 6^4y = 6^3y−2 please help

Harman [31]

Answer:

6^4=1296

6^3=216

1296.y= 216. Y-2

1296.y -216. Y=-2

1080.y=-2

Y=-1/540

Step-by-step explanation:

6 0

3 years ago

Write the polynomial in standard form 8-5x+x^3-2x^4

yan [13]

Answer:

-2x^4+x^3-5x+8

Step-by-step explanation:

8-5x+x^3-2x^4

Write the polynomial from highest powers of x to lowest

-2x^4+x^3-5x+8

8 0

3 years ago

What is the volume of the triangular prism in cubic centimeters?

kumpel [21]

The volume is 300 cubic centimeters for a triangular prism.

4 0

2 years ago

Solve: This month Salesperson A made 11% of $67,530. Salesperson B made 8% of $87,740. Who made more commission this month? How

alina1380 [7]

Salesperson a made more commission and made a total of $74958

4 0

3 years ago

Read 2 more answers