Answer:
68% of jazz CDs play between 45 and 59 minutes.
Step-by-step explanation:
<u>The correct question is:</u> The playing time X of jazz CDs has the normal distribution with mean 52 and standard deviation 7; N(52, 7).
According to the 68-95-99.7 rule, what percentage of jazz CDs play between 45 and 59 minutes?
Let X = <u>playing time of jazz CDs</u>
SO, X ~ Normal(
)
The z-score probability distribution for the normal distribution is given by;
Z =
~ N(0,1)
Now, according to the 68-95-99.7 rule, it is stated that;
- 68% of the data values lie within one standard deviation points from the mean.
- 95% of the data values lie within two standard deviation points from the mean.
- 99.7% of the data values lie within three standard deviation points from the mean.
Here, we have to find the percentage of jazz CDs play between 45 and 59 minutes;
For 45 minutes, z-score is =
= -1
For 59 minutes, z-score is =
= 1
This means that our data values lie within 1 standard deviation points, so it is stated that 68% of jazz CDs play between 45 and 59 minutes.
We have the given number =
660
Now, explain the relationship of 6s in the given number.
=> 6 = hundreds
=> 6 = tens
=> 0 = ones
This is also another form:
=> 6 = 600
=> 6 = 60,
now, notice that the first value of 6 in the leftmost side is 10 times
higher than the next number 6.
=> 60 x 10 = 600.
Thus, 600 is 10 times greater than 60 and vice versa.
Answer:
Critical Value
Step-by-step explanation:
The critical value separates the region of rejection from the region of non rejection.
We define critical values as:
- Critical value helps us to give the decision rule for the rejection or acceptance of null hypothesis.
- Critical value separates the acceptance region from the rejection region.
- These are referred to as cut-off values that define regions where the test statistic is unlikely to lie.
- The critical value depends on the kind of test being performed and the significance level.
Since it’s vertical it would be x=-7