Answer:
<h2>1.84feet</h2>
Step-by-step explanation:
Using the formula for finding range in projectile, Since range is the distance covered in the horizontal direction;
Range 
U is the velocity of the arrow
H is the maximum height reached = distance below the bullseye reached by the arrow.
R is the horizontal distance covered i.e the distance of the target from the archer.
g is the acceleration due to gravity.
Given R = 60ft, U = 250ft/s, g = 32ft/s H = ?
On substitution,

Squaring both sides we have;

The arrow will hit the target 1.84feet below the bullseye.
I got 11.5 lol I don’t really know why
the question does not present the options, but this does not interfere with the resolution
we know that
if a and b are parallel lines
so
1) m∠2=58°------> by corresponding angles
2) m∠1=4x-10------> by alternate exterior angles
3) [m∠2+m∠(3x-1)]+m ∠1=180°------> by supplementary angles
58+(3x-1)+4x-10=180
7x=180-47
7x=133
x=19°
4) angle (4x-10)=-4*19-10-------> 66°
5) angle 3x-1=3*19-1-------> 56°