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marusya05 [52]
4 years ago
5

I NEED HELP MAN PLEASE!!!! nobody is helping rn ):

Mathematics
1 answer:
igor_vitrenko [27]4 years ago
8 0
B is the first term
c is the common ratio

if the first term is x and the 2nd is y then x times c=y

so
-5 times what=10?
what=-2
c=-2
the first term is -5

-5(-2)^(n-1)

b=-5
c=-2
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Answer:

Below.

Step-by-step explanation:

The correct answer is D. Average daily balance method.

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Avanety of two types of snack packs are delivered to a store. The box plots compare the number of calories in each
AveGali [126]

Answer:

The number of calories in the packs of trail mix have a greater variation than the number of calories in the packs

of crackers

Step-by-step explanation:

IQR of trail mix data = 105 - 90 = 15

The range of cracker data = 100 - 70 = 30.

Therefore, the first option is NOT TRUE.

To check if option 2 is correct, calculate the lower limit to see if 70 is below the lower limit. If 70 is below the lower limit, then it is an outlier in the trail mix data.

Thus, Lower Limit = Q_1 - 1.5(IQR)

Q1 = 90,

IQR = 105 - 90 = 15

Lower Limit = 90 - 1.5(15)

Lower Limit = 90 - 22.5 = 67.5

70 is not less than the lower limit, therefore, 70 is not an outlier for the trail mix data. The second option is NOT TRUE.

The upper quartile of the trail mix data = 105.

The maximum value of the cracker data = 100.

Therefore, the third option is NOT TRUE.

Range can be used to determine how much variable there is in a data represented on a box plot. The greater the range value, the greater the variation.

Range of trail mix data = 115 - 70 = 45

Range of cracker data = 100 - 70 = 30.

<em>The range value for the number of calories in trail mix is greater than that for cracker, therefore, the number of calories in the packs of trail mix have a greater variation than the number of calories in the packs</em>

<em>of crackers.</em>

The fourth option is TRUE.

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The amount of time adults spend watching television is closely monitored by firms becayse this helps to determine advertising pr
Jet001 [13]

Answer:

Yes based on the result 0.4841 the internet users watch less TV because the mean would be placed at 0.5 and it is less than 0.5

Step-by-step explanation:

a)The variable "weekly time spent watching television" is normally distributed and is skewed right.

b) Mean = x` 2.35 hours

Standard deviation = s/√n = 1.93/√40=1.93/6.3245553= 0.3051598

c) P(2<X<3) = P (2-2.35/ 0.3051598< Z< 3 -2.35/ 0.3051598)

                    = P ( -1.14694 < Z <2.13003)

                     = 0.3729 + 0.4830

=0.8559

So the probability is 0.8559

(0.8559 we check the value of 2.13 from the normal distribution tables and add with the value of 1.14 to get the in between value -1.14694 < Z <2.13003)

d) Here n = 35 , s= 1.93 , mean = 2.35 and x= 1.89  

So Putting the values

P (X ≤ 1.89) = P (Z ≤ 1.89- 2.35/ 1.93 / √35)

              = P ( Z ≤ -0.238341/ 5.9160797)

                  = P ( Z ≤ -0.04028)

= 0.5 - 0.0159

= 0.4841

Similarly again subtracting from 0.5 the value from normal distribution table to get less than or equal to value.

Yes based on the result 0.4841 the internet users watch less TV because the mean would be placed at 0.5 and it is less than 0.5

8 0
3 years ago
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