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Svet_ta [14]
3 years ago
7

For f(x) = 0.02(2)^x find the average rate of change from x= 3 to x= 8

Mathematics
1 answer:
Fudgin [204]3 years ago
5 0

None of the offered choices is correct.

f(3) = 0.02·2³ = 0.02·8 = 0.16

f(8) = 0.02·2⁸ = 0.02·256 = 5.12

Then the average rate of change is

... (f(8) - f(3))/(8 - 3) = (5.12 -0.16)/5 = 4.96/5 = 0.992

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The surface area of the gift box is = A = \frac{1188}{7}x^{2}+ \frac{774}{7}x +\frac{132}{7}

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A = 2 \times \frac{22}{7} \times (3x+1) \times (6x+2) + 2 \times \frac{22}{7} \times (3x+1)^{2}

A = \frac{44}{7} (3x+1) \times (6x +2) + \frac{44}{7} (9x^{2} + 6x +1)\\A =\frac{132}{7}x + \frac{44}{7} \times (6x+2)+ \frac{396}{7}x^{2}+\frac{246}{7}x +\frac{44}{7}

A = \frac{792}{7}x^{2} +\frac{264}{7}x +\frac{264}{7}x + \frac{88}{7} + \frac{396}{7}x^{2} + \frac{246}{7}x + \frac{44}{7}

A = \frac{1188}{7}x^{2}+ \frac{774}{7}x +\frac{132}{7}

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