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horrorfan [7]
3 years ago
8

Lindsay invested $4500 at 4% interest compounded annually.

Mathematics
2 answers:
krok68 [10]3 years ago
7 0

Answer:

2161.10

Step-by-step explanation:

goldfiish [28.3K]3 years ago
5 0

Answer:

\$2,161.1

Step-by-step explanation:

we know that    

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

t=10\ years\\P=\$4,500\\ r=0.04\\n=1  

substitute in the formula above  

A=\$4,500(1+\frac{0.04}{1})^{1*10}  

A=\$4,500(1.04)^{10}

A=\$6,661.10    

Find the interest

I=A-P

I=\$6,661.10-\$4,500=\$2,161.1

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Step-by-step explanation:

The area of a sector has the formula

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A_s=\frac{5}{24}(3.14)(16) and

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8 0
3 years ago
(3x-5)/(x-5)&gt;=0 <br> How do I get the answers for this problem?
Diano4ka-milaya [45]
\frac{3x-5}{x-5} > 0 

First, note that x is undefined at 5. / x ≠ 5
Second, replace the inequality sign with an equal sign so that we can solve it like a normal equation. / Your problem should look like: \frac{3x-5}{x-5} = 0
Third, multiply both sides by x - 5. / Your problem should look like: 3x - 5 = 0
Forth, add 5 to both sides. / Your problem should look like: 3x = 5
Fifth, divide both sides by 3. / Your problem should look like: x = \frac{5}{3}
Sixth, from the values of x above, we have these 3 intervals to test: 
x < \frac{5}{3}
\frac{5}{3} < x < 5
x > 5
Seventh, pick a test point for each interval. 

1. For the interval x < \frac{5}{3} :
Let's pick x - 0. Then, \frac{3x0-5}{0-5} > 0
After simplifying, we get 1 > 0 which is true.
Keep this interval.

2. For the interval \frac{5}{3} < x < 5:
Let's pick x = 2. Then, \frac{3x2-5}{2-5} > 0
After simplifying, we get -0.3333 > 0, which is false.
Drop this interval.

3. For the interval x > 5:
Let's pick x = 6. Then, \frac{3x6-5}{6-5} > 0
After simplifying, we get 13 > 0, which is ture.
Keep this interval.
Eighth, therefore, x < \frac{5}{3} and x > 5

Answer: x < \frac{5}{3} and x > 5

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4 years ago
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3 years ago
A rectangular building with a square base is being designed to minimize heat loss. The building designers state that the volume
Arturiano [62]

Answer:

y = 4000/x²

Step-by-step explanation:

The volume of the building is expressed as;

V = x²y where;

x is the length and width of the base.

y is the height of the building

Given

Volume V = 4000m³

Substitute the given volume into the equation as shown;

4000 = x²y

Make y the subject of the formula by dividing both sides by x²

4000/x² = x²y/x²

4000/x² = y

Rearrange

y = 4000/x²

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8 0
3 years ago
The rectangle below has an area of x^2-7x+10square meters and a width of x - 5 meters. What expression represents the length of
jolli1 [7]

Answer:

L = (x - 2) meters

Step-by-step explanation:

The area of the rectangle = (x² - 7x + 10) m²

The width = (x - 5) m

length = ?

Area of a rectangle = length × width

x² - 7x + 10 = L(x -5)

note L = length

divide both sides by (x-5)

(x² - 7x + 10)/(x - 5) = L

L = x² - 7x + 10 / (x -5)

Factorize x² - 7x + 10

find the numbers you can multiply to give you 10 and also add to give you -7

The numbers are -2 and -5. Therefore,

x² - 2x - 5x + 10 = 0

x(x - 2) - 5(x - 2) = 0

(x-5)(x-2) = 0

Let us go back to our division

L = x² - 7x + 10 / (x -5)

x² - 7x + 10 = (x-5)(x-2)

L = (x-5)(x-2) / (x -5)

L = (x - 2) meters

7 0
3 years ago
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