Answer:
-2^5
Step-by-step explanation:
hope it helped. im not sure..
Answer:
Hello your question is incomplete below is the complete question
What is wrong with the equation? integral^2 _3 x^-3 dx = x^-2/-2]^2 _3 = -5/72 f(x) = x^-3 is continuous on the interval [-3, 2] so FTC2 cannot be applied. f(x) = x^-3 is not continuous on the interval [-3, 2] so FTC2 cannot be applied. f(x) = x^-3 is not continuous at x = -3, so FTC2 cannot be applied The lower limit is less than 0, so FTC2 cannot be applied. There is nothing wrong with the equation. If f(2) = 14, f' is continuous, and f'(x) dx = 15, what is the value of f(7)? F(7) =
answer : The value of f(7) = 29
Step-by-step explanation:
Attached below is the detailed solution
Hence : F(7) - 14 = 15
F(7) = 15 + 14 = 29
Answer:
The number is 79
Step-by-step explanation:
Let the number be 'x'
x + 17 = 96
Subtract 17 from both sides,
x + 17 -17 = 96 - 17
<h3> x = 79</h3>
The distance is determined by the y-intercept. The y-intercept for one line is 2 and the other is 4 so the distance from 2 to 4 is 2.
Answer: 0.8531
Step-by-step explanation:
Let x be the random variable that represents the readings on scientific thermometers .
Given : The readings on scientific thermometers are normally distributed,
Population mean : 
Standard deviation : 
Z-score : 
Now, the z-value corresponding to -1.05 : 
P-value = 

Hence, the probability of the reading greater than -1.05 in degrees Celsius.= 0.8531