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2 years ago

In the figure, AB| |CD. ∠AEB and ∠CED are congruent 1 .

Mathematics

2 answers:

MatroZZZ [7]2 years ago

7 0

Answer:

2. is B. BED. I don't know 1. but I do know that C is wrong for that question so it is either A or B.

Inessa [10]2 years ago

5 0

Answer:

1. B. By the vertical angles theorem.

2. ∠BED

Step-by-step explanation:

We have that, AB || CD and the two lines in between them are intersecting each other.

Since, we know that,

Vertical Angles Theorem states that 'Two opposite angles of the intersecting lines are congruent'.

So, as the lines are intersecting, we get by 'Vertical Angles Theorem',

∠AEB ≅ ∠CED and ∠AEC ≅ ∠BED.

You might be interested in

The data shown represent the number of runs made each year during Bill Mazeroski’s career. Check for normality.

const2013 [10]

Answer:

The given data is not normal.

Step-by-step explanation:

We are given the following data:

30, 59, 69, 50, 58, 71, 55, 43, 3, 66, 52, 56, 62, 36, 13, 29, 17, 31

Condition for normality:

Mean = Mode = Median

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{800}{18} = 44.44$

Mode is the most frequent observation of the data.

Since all the value appeared once, there is no mode.

$Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}$

Sorted data: 3, 13, 17, 29, 30, 31, 36, 43, 50, 52, 55, 56, 58, 59, 62, 66, 69, 71

Median =

$=\dfrac{9^{th}+10^{th}}{2} = \dfrac{50+52}{2}=51$

Since the mean, mode and median of data are not equal, the data is not normal.

7 0

3 years ago

Which term best describes the association between variables A and B?

dimulka [17.4K]

Answer: Choice B) negative linear association

=================================

Reasoning:

The points all go downhill as you move from left to right. We can draw a straight line that is fairly close to all of them. This is known as the regression line. The regression line having a negative slope tells us the linear association is negative. This means the correlation coefficient r is negative, so, $-1 < r < 0$ (r = -1 is not possible as not all points fall on the same straight line)

4 0

3 years ago

What is two thirds of eight

AlladinOne [14]

5 + 0.33333...

If you don't immediately recognize 0.33333.... as 1/3 (a very common fraction you should memorize), you can do the following. 

x = 0.33333... 

Multiply that by 10 to shift everything 1 place to the left: 
10x = 3.33333... 

Now subtract: 
10x - x = 3.33333... - 0.33333... 
9x = 3 
x = 3/9 
x = 1/3 

Answer: 
5 1/3 

P.S. Here's a shortcut way to turn a repeating decimal into a fraction. 

1) Take the repeated part and put it over an equivalent number of nines. 

Example: 
0.57575757... = 57/99 

At that point, see if you can reduce the fraction: 
= 19/33 

Another example: 
0.123123123... = 123/999 
= 41/333 

So in your example: 
5.33333... = 5 + 0.33333... 
= 5 + 3/9 
= 5 1/3

8 0

3 years ago

Which is the following points is NOT a solution to the inequality y > - x + 3? —a. ( -2,6)b. (5,-1)c. (2,0)d. (0,3)

CaHeK987 [17]

Given -

y > - x + 3

To Find -

The points which is NOT a solution to the inequality

Step-by-Step Explanation -

We will put the value of each in inequality and then see if it satisfies the given condition or not.

a. ( -2,6)

So, x = -2 and y = 6 in y > - x + 3

= 6 > - (-2) + 3

= 6 > 5 (Correct Solution)

b. (5,-1)

So, x = 5 and y = -1 in y > - x + 3

= -1 > -5 + 3

= -1 > -2 (Correct Solution)

c. (2,0)

So, x = 2 and y = 0 in y > - x + 3

= 0 > -2 + 3

= 0 > 1 (Incorrect Solution)

d. (0,3)

So, x = 0 and y = 3 in y > - x + 3

= 3 > -0 + 3

= 3 > 3 (Incorrect Solution)

Final Answer -

The points which is NOT a solution to the inequality =

c. (2,0)

d. (0,3)

3 0

11 months ago

A trapezoid has 9.2 inches base and 3.5 inches base, as well as 17 inches height. What is the area?

Tju [1.3M]

107.95 $in^{2}$

The area of a trapezoid is as follows:

A = $\frac{a + b}{2} h$

A and B are the lengths of the parallel lines of trapezoids. The parallel lines in this problem are 3.5 and 9.2. After adding those and dividing by 2, we multiply 17 to find the area of the trapezoid. (This is also shown in the attached picture)

4 0

3 years ago

In the figure, AB| |CD. ∠AEB and ∠CED are congruent __1__ .

In the figure, AB| |CD. ∠AEB and ∠CED are congruent 1 .