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adoni [48]
3 years ago
8

Students in 10th and 11th grade were asked whether they have a job. The raw data was converted to relative frequencies and recor

ded in the table below.
A 4-column table with 3 rows. The first column has no label with entries job, no job, total. The second column is labeled tenth grade with entries 0.14, 0.86, 1. The third column is labeled eleventh grade with entries 0.25, 0.75, 1. The fourth column is labeled total with entries 0.20, 0.80, 1.

Given the conditional relative frequency table by column, what does the 0.14 represent?
Given that a student is a 10th grader, there is a 14% chance he or she has a job.
Given that a student has a job, there is a 14% chance he or she is a 10th grader.
14% of the students surveyed are 10th graders who have a job.
14% of the students are 10th graders.
Mathematics
2 answers:
Vladimir [108]3 years ago
7 0

Answer:

A) Given that a student is a 10th grader, there is a 14% chance he or she has a job.

Step-by-step explanation:

Marta_Voda [28]3 years ago
4 0

Answer:

A.

Given that a student is a 10th grader, there is a 14% chance he or she has a job.

TOOK ONE FOR THE TEAM

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Prove:
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Base Step: For n=1:
n\left(\frac12\right)^{n-1}=1\left(\frac12\right)^{0}=1
and
4-\dfrac{n+2}{2^{n-1}}=4-3=1
--------------------------------------------------------------------------

Induction Hypothesis: Assume true for n=k. Meaning:
1+2\left(\frac12\right)+3\left(\frac12\right)^{2}+...+k\left(\frac12\right)^{k-1}=4-\dfrac{k+2}{2^{k-1}}
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--------------------------------------------------------------------------

Induction Step: For n=k+1:
1+2\left(\frac12\right)+3\left(\frac12\right)^{2}+...+k\left(\frac12\right)^{k-1}+(k+1)\left(\frac12\right)^{k}

by our Induction Hypothesis, we can replace every term in this summation (except the last term) with the right hand side of our assumption.
=4-\dfrac{k+2}{2^{k-1}}+(k+1)\left(\frac12\right)^{k}

From here, think about what you are trying to end up with.
For n=k+1, we WANT the formula to look like this:
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That thing on the right hand side is what we're trying to end up with. So we need to do some clever Algebra.

Combine the (k+1) and 1/2, put the 2 in the bottom,
=4-\dfrac{k+2}{2^{k-1}}+\dfrac{(k+1)}{2^{k}}

We want to end up with a 2^k as our final denominator, so our middle term is missing a power of 2. Let's multiply top and bottom by 2,
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Distribute the -2 and combine the fractions together,
=4+\dfrac{-2k-4+(k+1)}{2^{k}}

Combine like-terms,
=4+\dfrac{-k-3}{2^{k}}

pull the negative back out,
=4-\dfrac{k+3}{2^{k}}

And ta-da! We've done it!
We can break apart the +3 into +1 and +2,
and the +0 in the bottom can be written as -1 and +1,
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Answer:

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Step-by-step explanation:

38.12 + 12.24 = 50.36

6 is near 10

50.36 = 50.4

7 0
3 years ago
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