Answer:
what's the question?
Step-by-step explanation:
and the problem?
Answer:
0.405 or 40.5%
Step-by-step explanation:
Let event A=having a periodontal disease
event B=having a heart attack
we are given
P(A)=P(having a periodontal disease)=0.30
P(B)=P(having a heart attack)=0.15
P(A/B)=P(have a periodontal disease/have a heart attack)=0.81
P(B/A)=P(have a heart attack/have a periodontal disease)=?
P(A/B)=P(A∩B)/P(B)
P(A∩B)=P(B)*P(A/B)=0.15*0.81=0.1215
P(B/A)=P(A∩B)/P(A)=0.1215/0.3=0.405
There is 40.5% probability that if someone has periodontal disease will have a heart attack.
Answer:
Yes. Fertilization increases grape yields by more than 5 pounds.
Step-by-step explanation:
Let f-fertilized and o-old(unfertilized)
#First, we use our data to calculate the standard error:

#State both null and alternative hypothesis:

#We determine our degrees of freedom as 87.02(using R), we now compute the t-value as:

Since, the p-value is low, we Reject the null hypothesis. The is enough evidence suggesting that grape yields increase by more than 5 pounds than mean yields of unfertilized grapes.
Answer:
The standard deviation used in the test statistic is 0.04.
Step-by-step explanation:
A single proportion <em>z</em>-test can be used to determine whether the proportion of people in Norway with a blood type of A positive is different from that in the United States.
The proportion of people in Norway with a blood type of A positive is 36% or 0.36.
The hypothesis can be defined as:
<em>H₀</em>: The proportion of people in Norway with a blood type of A positive is 36%, i.e. <em>p</em> = 0.36.
<em>Hₐ</em>: The proportion of people in Norway with a blood type of A positive is different from 36%, i.e. <em>p</em> ≠ 0.36.
The test statistic is:

The information provided is:
<em>p</em> = 0.36
<em>n</em> = 150
Compute the standard deviation used in the test statistic as follows:



Thus, the standard deviation used in the test statistic is 0.04.