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creativ13 [48]
3 years ago
9

PLEEAASEE HELP!!! Suppose Q and R are independent events. Find P(Q and R) if P(Q) = 4/5 and P(R) = 4/11.

Mathematics
2 answers:
kari74 [83]3 years ago
5 0
The answer is C. 16/55 because P(Q and R) = P (Q) . P (R) (for independent events Q and R) 

So, the prob. is 4/5 * 4/11 = 16/55 = D. 
zepelin [54]3 years ago
4 0
It is A. 64/55 4 x 4 64
-- -- =
5 x 11 55
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Levart [38]
Divide the shape into two parts, square triangle, the square is easy 2x2=4. The second part you know the length is 2 as 4-2=2, and because it is half of a square, it will be half of the area, so total answer is 6
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3 years ago
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i am measurng two line segments the first line is 30centi meter long the second line segment is 500milli meter how long are the
Alexeev081 [22]

Answer    

Find out the how long are the two line segments together answer in cm .

To prove

As given

i am measurng two line segments the first line is 30centimeter long.

The second line segment is 500 millimeter .

As

1 millimeter = 0.1 centimeter

Now convert  500 millimeter into centimeter .

500 millimeter = 500 × 0.1 centimeter

                         = 50 centimeter

Thus second line segment be  50 centimeter long .

Total length of  two line segments = 30 + 50

                                                        = 80 cm

Therefore the 80 cm long are the two line segments together answer in cm .




8 0
3 years ago
The gas law for an ideal gas at absolute temperature T (in kelvins), pressure P (in atmospheres), and volume V (in liters) is PV
JulijaS [17]

Answer:

\frac{dT}{dt}=3.78^{\circ}K/min

Step-by-step explanation:

We have to calculate the time derivative of T=PV/nR with P and V variable and n and R constants. This is:

\frac{dT}{dt} =\frac{d\frac{PV}{nR}}{dt}=\frac{1}{nR}\frac{d(PV)}{dt}

What we have to do is the derivative of a product:

\frac{d(PV)}{dt}=P\frac{dV}{dt}+V\frac{dP}{dt}

Substituting, we have:

\frac{dT}{dt} =\frac{P\frac{dV}{dt}+V\frac{dP}{dt}}{nR}

where all these values are given since the time derivatives of P and V are their variation rate, using minutes.

We then substitute everything, noticing that already everything is in the same system of units so they cancel out:

\frac{dT}{dt}=\frac{P\frac{dV}{dt}+V\frac{dP}{dt}}{nR}=\frac{(8atm)(0.16L/min)+(13L)(0.14atm/min)}{(10mol)(0.0821Latm/mol^{\circ}K)}

And then just calculate:

\frac{dT}{dt}=3.78^{\circ}K/min

6 0
3 years ago
Earth has been charted with vertical and horizontal lines so that points can be named with coordinates. The horizontal lines are
inna [77]
<span>a. The radius of earth is about 6400 kilometers. Find the circumference of a great circle.

Circumference = 2π(radius) = 2π(6400 km) = 40.212,39 km

b. Write an equation for the circumference of any latitude circle with angle theta

As stated, </span><span><span>the length of any parallel of latitude (this is the circumference of corresponding circle) is equal to the circumference of a great circle of Earth times the cosine of the latitude angle</span>:

=> Circumference = 2π*radius* cos(Θ) = 2 π*6400km*cos(Θ) = 40,212.39 cos(Θ)

Answer: circumference = 40,212.39 cos(Θ) km

c. Which latitude circle has a circumference of about 3593 kilometers?

Make </span><span><span>40,212.39 cos(Θ)</span> km = 3593 km

=> cos(Θ) = 3593 / 40,212.39 = 0.08935 => Θ = arccos(0.08935) = 84.5° = 1.48 rad

Answer: 1.48

d. What is the circumference of the Equator? </span>

For the Equator Θ = 0°

=> circumference = 40,213.49cos(0°) km = 40,212.49 km

Answer: 40,212.49 km

7 0
3 years ago
Use the following function rule to find f(3).
Vedmedyk [2.9K]

Answer:

f(3)= 33

Step-by-step explanation:

hello :

f(x) =8x+9

put x = 3    you have : f(3) =8(3)+9 = 24 + 9 =33

7 0
3 years ago
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