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Lesechka [4]
4 years ago
12

What is the speed of a bobsled whose distance-time graph indicates that it traveled 119m in 28s? m/s

Physics
1 answer:
Alexxx [7]4 years ago
4 0
Before we solve, let's use our formula for speed.
Speed is defined as distance divided by time.
S = D/T
We have 119m and 28s.
Our distance is 119m.
Our time is 28s.
Plug these numbers into the formula.

S = 119/28
Divide 119 by 28 to get our speed.
119/28 = 4.25.

Our speed is 4.25 m/s.

I hope this helps!
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A 4.5 kg bowling ball rolls down a 500m hill. How much potential energy does it lose?
lions [1.4K]

Answer:

22050 J

Explanation:

Given Mass of the ball, m = 4.5 Kg

Height, h =500 m

Acceleration due to gravity, g= 9.8m/s^{2}

To calculate the potential energy we use formula,

PE = mgh

Substituting the given values, we get

PE = 4.5× 9.8×500

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8 0
3 years ago
A crate with a mass of 175.5 kg is suspended from the end of a uniform boom with a mass of 94.7 kg. The upper end of the boom is
Rudiy27

The tension in the cable is equal to 323.5 N.

<h3>What is the tension in the cable?</h3>

The tension, T in the cable is determined by taking moments about the pivot  marked X.

The angles of the boom and the cable with the horizontal are first calculated.

Angle of the boom with horizontal, θ = tan⁻¹(5/10) = 26.56°

The angle of cable with horizontal, B = tan⁻¹(4/10) = 21.80

Taking moments about the pivot:

175.5 * cos 26.56 + 94.7 * cos 26.56 * 0.5 = T (sin(26.56 + 21.80) * 1

Tension = 241.68/0.747

Tension = 323.5 N

In conclusion, the tension in the cable helps to suspend the crate.

Learn more about tension at: brainly.com/question/24994188

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6 0
2 years ago
What is the quality of the sound of a fire truck’s siren when it moves toward a stationary hearer?
Doss [256]
<span>What is the quality of the sound of a fire truck’s siren when it moves toward a stationary hearer?
Its High Pitched

</span>

What is the quality of the sound of a fire truck’s siren when it moves away from a stationary hearer?

Its Low Pitched

6 0
3 years ago
Read 2 more answers
Assume that the solar radiation incident on Earth is 1330 W/m2 (at the top of the atmosphere). Find the total power radiated by
Temka [501]

Answer:

The total power radiated by the sun is 3.71×10^26W

Explanation:

The Earth is spherical in shape

Therefore, Area = 4πr^2 = 4×3.143×(1.489×10^11)^2 = 2.79×10^23m^2

Power radiated by the Sun = solar radiation on Earth × Area = 1330W/m^2 × 2.79×10^23m^2 = 3.71×10^26W

8 0
3 years ago
PLEASE HELP!!!!!!!!!
Strike441 [17]
I think it’s Malleability
8 0
3 years ago
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