Kepler's third law is called the law of harmonies<span> which calculates the period and radius of orbit of a planet with the given dimensions and period of another planet. The comparison is proportional to the square of period and inversely proportional to the cube of the distance. Hence when the distance is placed three times the original ((3D)^3), the period should increase by sqrt of 27 times of 5.20 times the original period,</span>
By 272.7 degrees angle has planet Y rotated through during this time.
<h3 /><h3>What is Kepler's 3rd law?</h3>
The cubes of the semi-major axes of the planets' orbits are precisely proportional to the squares of the planets' orbital periods. According to Kepler's Third Law, as an orbiting planet's radius rises, so does the time of its orbit around the Sun.
Using Kepler's 3rd law, which says that the period of any planet's orbit squared is proportional to the radius of the orbit cubes, we can establish that
(period X / period Y)^2 = (radius X / radius Y)^3
(period X / period Y)^2 = 2^3 = 8
take sq root
period X / period Y = √8 = 2.82≅ 3
this means it takes planet X 2.82≅ 3 times longer to go through one orbit... so planet Y travels 2.82≅ 3 times as far (in its orbit...) as planet X!
This means...
planet Y travels 3 * 90.9 = 272.7 degrees
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Answer:
= 40 cm
Explanation:
given data
string length = 30 cm
solution
we take here equation of length that is
L =
...............1
so
total length will be here


so
will be

= 40 cm