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anygoal [31]
3 years ago
14

A protostar forms once the nebular cloud condenses and the core begins

Physics
2 answers:
Fantom [35]3 years ago
6 0
A protostar forms once the nebular cloud condenses and the core begins nuclear fusion.
enyata [817]3 years ago
4 0

Answer:

Explanation:

A protostar forms once the nebular cloud condenses and the core begins HEAT.

A protostar is a very young star that is still gathering mass from its parent molecular cloud. The protostellar phase is the earliest one in the process of stellar evolution. A protostar is the earliest stage in star formation in the universe.  When the gas cloud begins to collapse on its own weight, the core begins to heat up. The heat is due to the force of compression of the dust and gas under its gravity. When the pressure and temperatures become high enough, the hydrogen in the core begins to fuse.

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En la Tierra, una balanza muestra que tu peso es 585 N.
ra1l [238]

Answer:

a) m = 59.63 [kg]

b) Wm = 95.41 [N]

Explanation:

El peso de un cuerpo se define como el producto de la masa por la aceleración gravitacional. DE esta manera tenemos:

W = m*g

Donde:

m = masa [kg]

g = gravedad = 9.81 [m/s^2]

m = W / g

m = 585 / 9.81

m = 59.63 [kg]

Es importante aclarar que la masa se conserva independientemente de la ubicación del cuerpo en el espacio.

Por ende su masa sera la misma en la luna.

El peso en la luna se calcula como Wm y es igual a:

Wm = 59.63 * 1.6 = 95.41 [N]

5 0
3 years ago
2. This diagram represents a top-down view of an experiment on a table. The 250 g and 100 g masses are falling and are pulling t
Rasek [7]

Answer:

According to the data given in the question, experiment on table two pulling and falling masses are arranged in the fig. 250  g is pulling right side and   100 g pulling down. The gravitational force is common to both the masses, so we cannot say that the block moves towards heavier mass, also the block  does not move towards the lighter mass.

Obviously, the effect of heavier mass of 250 g is more on the block, so the block moves towards right bottom corner. i.e., diagonally between two masses


please find the attachment.

4 0
3 years ago
Read 2 more answers
9. A 12 v battery is connected to four 5 ohm light bulbs. What is the equivalent
vlabodo [156]
20 ohms 5 ohms
12volts
7 0
2 years ago
Determine the minimum applied force p required to move wedge a to the right. the spring is compressed a distance of 175 mm. negl
BARSIC [14]
<span>b. The coefficient of static friction for all contacting surfaces is μs=0.35. neglect friction at the rollers.

</span>
6 0
3 years ago
A penny rides on top of a piston as it undergoes vertical simple harmonic motion with an amplitude of 4.0cm. If the frequency is
aniked [119]

1) At the moment of being at the top, the piston will not only tend to push the penny up but will also descend at a faster rate at which the penny can reach in 'free fall', in that short distance. Therefore, at the highest point, the penny will lose contact with the piston. Therefore the correct answer is C.

2) To solve this problem we will apply the equations related to the simple harmonic movement, hence we have that the acceleration can be defined as

a = -\omega^2 A

Where,

a = Acceleration

A = Amplitude

\omega= Angular velocity

From a reference system in which the downward acceleration is negative due to the force of gravity we will have to

a = -g

-\omega^2 A = -g

\omega = \sqrt{\frac{g}{A}}

From the definition of frequency and angular velocity we have to

\omega = 2\pi f

f = \frac{1}{2\pi} \sqrt{\frac{g}{A}}

f = \frac{1}{2\pi} \sqrt{\frac{9.8}{4*10^{-2}}}

f = 2.5Hz

Therefore the maximum frequency for which the penny just barely remains in place for the full cycle is 2.5Hz

6 0
3 years ago
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