Answer:
a) m = 59.63 [kg]
b) Wm = 95.41 [N]
Explanation:
El peso de un cuerpo se define como el producto de la masa por la aceleración gravitacional. DE esta manera tenemos:
W = m*g
Donde:
m = masa [kg]
g = gravedad = 9.81 [m/s^2]
m = W / g
m = 585 / 9.81
m = 59.63 [kg]
Es importante aclarar que la masa se conserva independientemente de la ubicación del cuerpo en el espacio.
Por ende su masa sera la misma en la luna.
El peso en la luna se calcula como Wm y es igual a:
Wm = 59.63 * 1.6 = 95.41 [N]
Answer:
According to the data given in the question, experiment on table two pulling and falling masses are arranged in the fig. 250 g is pulling right side and 100 g pulling down. The gravitational force is common to both the masses, so we cannot say that the block moves towards heavier mass, also the block does not move towards the lighter mass.
Obviously, the effect of heavier mass of 250 g is more on the block, so the block moves towards right bottom corner. i.e., diagonally between two masses
please find the attachment.
<span>b. The coefficient of static friction for all contacting surfaces is μs=0.35. neglect friction at the rollers.
</span>
1) At the moment of being at the top, the piston will not only tend to push the penny up but will also descend at a faster rate at which the penny can reach in 'free fall', in that short distance. Therefore, at the highest point, the penny will lose contact with the piston. Therefore the correct answer is C.
2) To solve this problem we will apply the equations related to the simple harmonic movement, hence we have that the acceleration can be defined as

Where,
a = Acceleration
A = Amplitude
= Angular velocity
From a reference system in which the downward acceleration is negative due to the force of gravity we will have to



From the definition of frequency and angular velocity we have to




Therefore the maximum frequency for which the penny just barely remains in place for the full cycle is 2.5Hz