All categories

3 years ago

A recipe calls for 2 cups of water for every 3 cups of flour. How much water is needed if you use 12 cups of flour?

Mathematics

1 answer:

Tju [1.3M]3 years ago

6 0

Answer:

8 cups of water

Explanation:

2 cups of water = 3 cups of flour

x cups of water = 12 cups of flour

12/3=4

2x4=8

You might be interested in

Anyone happen to know this? Thanks.

Step2247 [10]

Answer:

Step-by-step explanation:

given y = f(x) then y = f(x + c) represents a horizontal translation

• If c > 0 then shift to the left of c units

• If c < 0 then shift to the right of c units

given y = f(x) then f(x) + c represents a vertical translation

• If c > 0 then shift up by c units

• If c < 0 then shift down by c units

here f(x) = | x | thus a shift of 4 units right is f(x) = | x - 4 |

and a shift of 6 units up gives

f(x) = | x - 4 | + 6 → A

8 0

3 years ago

FIRST RIGHT GETS BRAINLIEST

Luda [366]

4 is the median! Because the middle numbers are 8 and 4 and if you add them you get 12 and 12 divided by 2 equals 4

5 0

3 years ago

In a right triangle, angle is an acute angle and sin angle = 4/9. Evaluate the other five trigonometric functions of angle.

kkurt [141]

Answer:

Part 1) $cos(A)=\frac{\sqrt{65}}{9}$

Part 2) $tan(A)=4\frac{\sqrt{65}}{65}$

Part 3) $cot(A)=\frac{\sqrt{65}}{4}$

Part 4) $sec(A)=9\frac{\sqrt{65}}{65}$

Part 5) $csc(A)=\frac{9}{4}$

Step-by-step explanation:

Let

A------> the angle

we have that

$sin(A)=\frac{4}{9}$

step 1

Find the cos(A)

we know that

$cos^{2}(A)+sin^{2}(A)=1$

substitute the value of sin(A)

$cos^{2}(A)+(\frac{4}{9})^{2}=1$

$cos^{2}(A)=1-(\frac{4}{9})^{2}$

$cos^{2}(A)=1-(\frac{16}{81})$

$cos^{2}(A)=(\frac{65}{81})$

$cos(A)=\frac{\sqrt{65}}{9}$

step 2

Find the tan(A)

we know that

$tan(A)=\frac{sin(A)}{cos(A)}$

substitute the values

$tan(A)=\frac{\frac{4}{9}}{\frac{\sqrt{65}}{9}}$

$tan(A)=\frac{4}{\sqrt{65}}$

$tan(A)=4\frac{\sqrt{65}}{65}$

step 3

Find the cot(A)

we know that

$cot(A)=\frac{1}{tan(A)}$

we have

$tan(A)=\frac{4}{\sqrt{65}}$

substitute

$cot(A)=\frac{1}{\frac{4}{\sqrt{65}}}$

$cot(A)=\frac{\sqrt{65}}{4}$

step 4

Find the sec(A)

we know that

$sec(A)=\frac{1}{cos(A)}$

we have

$cos(A)=\frac{\sqrt{65}}{9}$

substitute

$sec(A)=\frac{1}{\frac{\sqrt{65}}{9}}$

$sec(A)=\frac{9}{\sqrt{65}}$

$sec(A)=9\frac{\sqrt{65}}{65}$

step 5

Find the csc(A)

we know that

$csc(A)=\frac{1}{sin(A)}$

we have

$sin(A)=\frac{4}{9}$

substitute the value

$csc(A)=\frac{1}{\frac{4}{9}}$

$csc(A)=\frac{9}{4}$

5 0

3 years ago

Zoom bomb this let's go get on at 12:45

Afina-wow [57]

Answer:

am? bc pm is past

Step-by-step explanation:

also are you f or m

5 0

3 years ago

Read 2 more answers

Find a product that only contains 2 and 9

Vlada [557]

Its 18 because I know .

3 0

3 years ago

Read 2 more answers