The numbers in the sequence will be 40, 80, and 160.
<h3>How to get the values?</h3>
Let x be the first number in the sequence, so the first three numbers are {x, 0.5x, 0.5²x}.
Then
{x/4 + 10, 0.5x - 10, 2(0.5²x) + 10}
0.5x - 10 = x/4 + 10 + c = x/2 - 10 = x/4 + 10 + c
2(0.5²x) + 10 = 0.5x - 10 + c = x/2 + 10 = x/2 - 10 + c
Solve the second equation for c :
x/2 + 10 = x/2 - 10 + c
c = 20
Substitute this into the first equation and solve for x :
x/2 - 10 = x/4 + 10 + 20
x/4 = 40
x = 160
Then the terms are {160, 80, 40}
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If that is a decimal the 1 would be in the tenths. If it is a whole number it would be in the hundred thousands
Answer:
6
Step-by-step explanation:
im just gonna name these couples by numbers 1 , 2 and 3 and each couple will take up 2 seats together.
1 2 3
3 2 1
2 3 1
1 3 2
2 1 3
3 1 2
Answer:
x=0, x= (9+i square root35)/2, x= (9-i square root 35)/2
Step-by-step explanation:
Answer:
A. Increase sample size
Step-by-step explanation:
From the formula for estimating the confidence level interval for the mean:
X - Z × s/sqrt n where; X = sample mean; Z = z value corresponding to 95%;
s = standard deviation and n = sample size
It is evident from the equation that the confidence interval for the mean is inversely proportional to the sample size (n), hence increasing the sample size will result in a reduced interval width.
