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steposvetlana [31]
3 years ago
6

The Sugar Sweet Company will choose from two companies to transport its sugar to the market. The first company charges $4500 to

rent trucks plus an additional fee of $200.50 for each ton of sugar. The second company charges $4197 to rent trucks plus an additional fee of $225.75 for each ton of sugar.
1)For what amount of sugar do the two companies charge the same?
2)What is the cost when the two companies charge the same?
WILL GIVE BRAINLIEST!!

Mathematics
1 answer:
otez555 [7]3 years ago
6 0

Answer:

1. 12 tonnes of sugar

2. 6906 dollars

Please mark Brainliest if this helps!

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Identify the following sequences as arithmetic, geometric, or neither. For the arithmetic and geometric sequences, identify the
Lapatulllka [165]

Hence,

a. 12, 144, 1728,..  => Geometric

b. 0,5, 10, 15, 20, 25,...  => Arithmetic

c. 0,4, 16, 36, 64,...  => Neither arithmetic nor geometric

d. 1.5, 2.25, 3.375, 5.0625,... => Geometric

Step-by-step explanation:

In order to identify the sequence as geometric or arithmetic sequence, we find the common difference and common ratio of the sequence. If the common difference is same, it is an arithmetic sequence and if the common ratio is same the sequence is a geometric sequence

Common difference is the difference between consecutive terms of an arithmetic sequence and common ration is the ratio between two consecutive terms of a sequence

So,

<u>a. 12, 144, 1728,..</u>

Here,

a_1=12\\a_2=144\\a_2=1728

Common difference:

d=a_2-a_1 = 144-12 = 132\\=a_3-a_2 = 1728-144=1584

Common Ratio:

r=\frac{a_2}{a_1} =\frac{144}{12} = 12\\=\frac{a_3}{a_2}=\frac{1728}{144} =12

As the common ratio is same, the given sequence is a geometric sequence.

<u></u>

<u>b. 0,5, 10, 15, 20, 25,...</u>

Here,

a_1 = 0\\a_2 =5\\a_3 =10

Common difference:

d=a_2-a_1 = 5-0 = 5\\d=a_3-a_2 = 10-5 = 5

As the common difference is same, the given sequence is an arithmetic sequence

<u></u>

<u>c. 0,4, 16, 36, 64,...</u>

Here

a_1 = 0\\a_2 =4\\a_3 = 16\\a_4 = 36

Common Difference:

d= a_2-a_1 = 4-0 = 4\\a_3-a_2 = 16-4 = 12

<u></u>

Common Ratio:

r=\frac{a_2}{a_1} = \frac{4}{0} = Doesn't\ exist

Neither the common ratio nor common difference are same, so the given sequence is neither arithmetic nor geometric

<u>d. 1.5, 2.25, 3.375, 5.0625,...</u>

Here

a_1 = 1.5\\a_2 = 2.25\\a_3 = 3.375

<u></u>

Common Difference:

d=a_2-a_1 = 2.25-1.5 = 0.75\\a_3-a_2 =3.375-2.25 = 1.125[/tex]Common Ratio: [tex]r=\frac{a_2}{a_1} = \frac{2.25}{1.5}=1.5\\=\frac{a_3}{a_2} =\frac{3.375}{2.25}=1.5

As the common ratio is same, given sequence is geometric

Hence,

a. 12, 144, 1728,..  => Geometric

b. 0,5, 10, 15, 20, 25,...  => Arithmetic

c. 0,4, 16, 36, 64,...  => Neither arithmetic nor geometric

d. 1.5, 2.25, 3.375, 5.0625,... => Geometric

<u>Keywords: Sequence, Ratio</u>

<u>Learn more about sequences at:</u>

  • brainly.com/question/3783529
  • brainly.com/question/3799248

#LearnwithBrainly

4 0
3 years ago
What is the equation of the quadratic graph with a focus of (1, 1) and a directrix of y = −1?
JulsSmile [24]
Alright,
directix is y=something so it opens down or up

we use
(x-h)²=4p(y-k)
the vertex is (h,k)
and p is distance from focus to vertex
if focus is above directix, p is positive
if focus is below directix, p is negative

so we gts

focus=(1,1)
directix is y=-1
1>-1
focus is above

oh, vertex is in middle of focus and directix
so
beteeen (1,1) and y=-1 is, hmm
that is a distance of 2 vertically
2/2=1
1 down from (1,1) is (1,0)
vertex is (1,0)
p=1

so
(x-1)²=4(1)(y-0)
solving for y to get into f(x)=something form
(x-1)²=4y
y=1/4(x-1)²
f(x)=1/4(x-1)²

4th option
6 0
3 years ago
10 percent of 145..........
jeka57 [31]
To get this, take 0.10 x 145 = 14.5
3 0
3 years ago
Read 2 more answers
Guys i rlly need u to look up these nams!!
zvonat [6]

Answer:

Ok I will

Step-by-step explanation:

Mark as Brainliest :)

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4 0
3 years ago
Gerald drives 200 miles in 2 1/2 hours. what is gerald's average speed?
Dimas [21]

Answer:

80mph

Step-by-step explanation:

200 divided by 2 1/2 is 80.

3 0
3 years ago
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