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steposvetlana [31]
3 years ago
6

The Sugar Sweet Company will choose from two companies to transport its sugar to the market. The first company charges $4500 to

rent trucks plus an additional fee of $200.50 for each ton of sugar. The second company charges $4197 to rent trucks plus an additional fee of $225.75 for each ton of sugar.
1)For what amount of sugar do the two companies charge the same?
2)What is the cost when the two companies charge the same?
WILL GIVE BRAINLIEST!!

Mathematics
1 answer:
otez555 [7]3 years ago
6 0

Answer:

1. 12 tonnes of sugar

2. 6906 dollars

Please mark Brainliest if this helps!

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Over the summer, for every 11 okra seeds Dana planted, 6 grew into plants. If he planted 110 okra seeds, how many grew into plan
PilotLPTM [1.2K]

Answer:

A

Step-by-step explanation:

write it as a ratio

11:6 = 110: x

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3 years ago
Y=-x^2+6x-4<br> Find the Axis of Symmetry and the Vertex, Also solve the whole equation.
Inessa [10]

Answer:

1. <em>Axis of symmetry</em>: x = 3

2. <em>Vertex:</em> (3,5)

3. <em>Solution of the equation</em>:

<u />

  • x-intercepts:

               (3-\sqrt{5},0) \\\\(3+\sqrt{5},0)

  • y-intercept: (0, -4)

Explanation:

<u>1. Equation:</u>

    y=-x^2+6x-4

<u>2. </u><em><u>Axis of symmetry:</u></em>

That is the equation of a parabola, whose standard form is:

                 y=ax^2+bx+c

Where:    

                 a=-1;b=6;c=-4

The axis of symmetry is the vertical line with equation:

               x=-b/2a

Substitute  a=-1,\text{ and }b=6

          x=-6/[(2)(-1)]=-6/(-2)=3

Thus, the axis of symmetry is:

            x=3

<em><u>3. Vertex</u></em>

<em><u /></em>

The x-coordinate of the vertex is equal to the axys of symmetry, i.e x = 3.

To find the y-xoordinate, substitute this value of x into the equation for y:

               y=-x^2+6x-4\\\\y=-(3)^2+6(3)-4=-9+18-4=5

Therefore, the vertex is (3, 5)

<u>4. Find the x-intercepts</u>

The x-intercepts are the roots of the equation, which are the points wher y = 0.

        y=-x^2+6x-4=0

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       x=\frac{-b\pm \sqrt{b^2-4ac} }{2a} \\\\x=\frac{-6\pm\sqrt{(-6)^2-4(-1)(-4)} }{2(-1)}\\\\x_1=3-\sqrt{5} \\\\x_2=3+\sqrt{5}

<u>5. Find the y-intercept</u>

<u />

The y-intercet is the value of y when x=0:

         y=-x^2+6x-4\\\\y=-(0)^2+6(0)-4=-4

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Answer:

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Step-by-step explanation:

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Perimeter and Circumference! Only 5 questions
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Answer:

1) 17.5

2)43.96

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Step-by-step explanation:

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VMariaS [17]

Answer:

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Step-by-step explanation:

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