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3 years ago

Describing Acceleration

Physics

2 answers:

vagabundo [1.1K]3 years ago

6 0

Answer: Negative acceleration occurs when an object slows down in the positive direction.

Positive acceleration occurs when an object speeds up in the positive direction.

Explanation: Acceleration can be positive or negative. A negative acceleration is also known as deceleration. And deceleration occurs when an object is coming to rest. While acceleration simply means that an object is Speeding up.

Negative acceleration occurs when an object slows down in the positive direction.

Positive acceleration occurs when an object speeds up in the positive direction.

Aleonysh [2.5K]3 years ago

5 0

Answer: A, C,D,F

A)Neg. acc. occurs when an object slows down in the pos. direct.

C)Neg. acc. occurs when an object slows down in the neg. direct.

D)Pos. acc. occurs when an object speeds up in the pos. direct.

F) Pos. acc. occurs when an object slows down in the neg. direct.

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3 years ago

A screen is placed 1.60 m behind a single slit. The central maximum in the resulting diffraction pattern on the screen is 1.40 c

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Answer:

distance between the two second-order minima is 2.8 cm

Explanation:

Given data

distance = 1.60 m

central maximum = 1.40 cm

first-order diffraction minima = 1.40 cm

to find out

distance between the two second-order minima

solution

we know that fringe width = first-order diffraction minima /2

fringe width = 1.40 /2 = 0.7 cm

and

we know fringe width of first order we calculate slit d

β1 = m1λD/d

d = m1λD/β1

and

fringe width of second order

β2 = m2λD/d

β2 = m2λD / ( m1λD/β1 )

β2 = ( m2 / m1 ) β1

we know the two first-order diffraction minima are separated by 1.40 cm

y = 2β2 = 2 ( m2 / m1 ) β1

put here value

y = 2 ( 2 / 1 ) 0.7

y = 2.8 cm

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Read 2 more answers

A wave has a wavelength of 0.02m and period of 8.0*10^-2 seconds. calculate it's speed. (showing working)

erik [133]

Answer:

$v = 0.25m/s$

Explanation:

Given

$\lambda = 0.02m$ --- Wavelength

$T = 8.0 * 10^{-2}s$ --- Period

Required

Determine the velocity of the wave

This is calculated using:

$v = \frac{\lambda}{T}$

$v = \frac{0.02m}{8.0*10^{-2}s}$

$v = \frac{0.02m}{8.0*0.01s}$

$v = \frac{0.02m}{0.08s}$

$v = 0.25m/s$

<em>Hence, the velocity is 0.25m/s</em>

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3 years ago