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2 years ago

Can you please help me on all of these!!!! Please

Physics

1 answer:

Aloiza [94]2 years ago

7 0

Answer:

differ from mechanical waves in that they do not require a medium to propagate. This means that electromagnetic waves can travel not only through the air and solid materials but also through the vacuum of space.

Explanation:

This means that electromagnetic waves can travel not only through the air and solid materials but also through the vacuum of space.

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Approximate the Sun as a uniform sphere of radius 6.96 X 108 m, rotating about its central axis with a period of 25.4 days. Supp

In-s [12.5K]

Answer:

T = 184 seconds

Explanation:

First in order to solve this, we need to know which is the expression to calculate the period. This is an exercise of angular velocity, so:

T = 2π/w

Where w: angular speed (in rad/s)

So, let's calculate first the innitial angular speed:

w = 2π/T

Converting days to seconds:

25.4 days * 24 h/day * 3600 s/h = 2,194,560 s

Then the angular speed:

w = 2π / 2,194,560 = 2.863x10^-6 rad/s

Now, the innitial angular momentum is:

I = (2/5)Mr² replacing data:

I = 2/5* (6.96x10^8)² * M = 1.94x10^17m² * M

so the initial angular momentum would be:

L = Iω = 2.863x10^-6 * 1.94x10^17 M

L = 5.55x10^11 m²/s * M = final angular momentum

Now the final I = 2/5Mr²

Final I = 2/5 * (6.37x10^6)² * M = 1.62x10^13m² * M

Then 5.55x10^11m²/s * M = 1.62x10^13m² * M * ω → M cancels

ω = 3.42x10^-2 rad/s

Then the new period

T = 2π/ω = 2*3.14 / 3.42x10^-2

T = 184 seconds

8 0

3 years ago

A certain carbon monoxide molecule consists of a carbon atom mc = 12 u and an oxygen atom mo = 17 u that are separated by a dist

kvasek [131]

Answer:

a) x_{cm} = m₂/ (m₁ + m₂) d , b) x_{cm} = 52.97 pm

Explanation:

The expression for the center of mass is

$x_{cm}$ = 1 / M ∑ $x_{i}$ $m_{i}$

Where M is the total masses, mI and xi are the mass and position of each element of the system.

Let's fix our reference system on the oxygen atom and the molecule aligned on the x-axis, let's use index 1 for oxygen and index 2 for carbon

x_{cm} = 1 / (m₁ + m₂) (0+ m₂ x₂)

Let's reduce the magnitudes to the SI system

m₁ = 17 u = 17 1,661 10⁻²⁷ kg = 28,237 10⁻²⁷ kg

m₂ = 12 u = 12 1,661 10⁻²⁷ kg = 19,932 10⁻²⁷ kg

d = 128 pm = 128 10⁻¹² m

The equation for the center of mass is

x_{cm} = m₂/ (m₁ + m₂) d

b) let's calculate the value

x_{cm} = 19.932 10⁻²⁷ /(19.932+ 28.237) 10⁻²⁷ 128 10-12

x_{cm} = 52.97 10⁻¹² m

x_{cm} = 52.97 pm

7 0

2 years ago

Can someone pls help me with this? Its due in 25 minutes

QveST [7]

The angle of reflection is 42 degrees because it says the angle of incidence is equal to the angle of reflection

5 0

3 years ago

Imagine that you are jumping up and down on a trampoline.

lions [1.4K]

Answer:

a. When you are pressing downwards the energy stored is potential elastic energy due to the elasticity of the stretchy skin.

b. When you are high up in the air the energy stored is potential energy due to your weight and the distance to the ground.

Hope this Helps!

If you have Any questions Please Ask.

5 0

2 years ago

A ball is thrown upward at time t=0 from the ground with an initial velocity of 4 m/s (~ 9 mph). Assume that g = 10 m/s^2. What

aleksandrvk [35]

Answer:

The greatest height reached by the ball is 0.8 m.

Explanation:

Given that,

Initial velocity = 4 m/s

We need to calculate the greatest height reached by the ball

Using equation of motion

$v^2=u^2+2gh$

Where, v = final velocity

u = initial velocity

g = acceleration due to gravity

Put the value in the equation

$0=4^2+2\times(-10)\times h$

$h =\dfrac{16}{20}$

$h =0.8\ m$

Hence, The greatest height reached by the ball is 0.8 m.

4 0

3 years ago