I am sorry but I do not see the underlined digit, but I will put it this way. 7 in the thousands place is worth 7000, 2 in the hundreds place is worth 200, 7 in the tens place is worth 70, and 0 in the ones place is worth 0.
Hope this helped!
Nate
Answer:
(x + 4) (x+6) +24 = 0
Step-by-step explanation:
y = mx + b
When a function is reflected over the y-axis, the b (2) stays the same but the slope (m) changes to its opposite sign.
since the slope is negative in this equation, it will become positive.
so the new fuction will be
y = 5x + 2
Answer:
the equation fits the situation, but the table doesn’t.
Step-by-step explanation:
For both functions, the lead roller coaster car starts at an initial height of 32 feet. This is the point (0,32), directly above Landon.
The car races past Landon’s field of vision (y = 0) after it moves a horizontal distance of 4 feet and then 8 feet with respect to the starting point. So, the correct function will have x-intercepts of 4 and 8.
Begin by checking the equation. Rewrite the equation in factored form:
f(x) =
− 11
+ 20x + 32
= (x + 1)(
− 12x + 32)
= (x + 1)(x − 4)(x − 8)
The equation has x-intercepts of 4 and 8.
But the table only has one x-intercept, located at (4,0). The point (8,160) is well out of Landon’s line of sight.
So, the equation fits the situation, but the table doesn’t.
Function assign value from one set to another. The value of f(5), if f(1) = 3.2 and f(x+1) = Five-halves(f(x)) is 125.
<h3>What is Function?</h3>
A function assigns the value of each element of one set to the other specific element of another set.
As it is given the value of the function f(1) is 3.2, while the value of f(x+1) is
, therefore, in order to find the value of f(5), we need to calculate the value of f(4).
f(2)
![f(x+1) = \dfrac{5}{2}[f(x)]\\\\f(2)=f(1+1) = \dfrac{5}{2}[f(1)]\\\\f(2) = 2.5 \times 3.2\\\\f(2) = 8](https://tex.z-dn.net/?f=f%28x%2B1%29%20%3D%20%5Cdfrac%7B5%7D%7B2%7D%5Bf%28x%29%5D%5C%5C%5C%5Cf%282%29%3Df%281%2B1%29%20%3D%20%5Cdfrac%7B5%7D%7B2%7D%5Bf%281%29%5D%5C%5C%5C%5Cf%282%29%20%3D%202.5%20%5Ctimes%203.2%5C%5C%5C%5Cf%282%29%20%3D%208)
f(3)
![f(x+1) = \dfrac{5}{2}[f(x)]\\\\f(3)=f(2+1) = \dfrac{5}{2}[f(2)]\\\\f(3) = 2.5 \times 8\\\\f(3) = 20](https://tex.z-dn.net/?f=f%28x%2B1%29%20%3D%20%5Cdfrac%7B5%7D%7B2%7D%5Bf%28x%29%5D%5C%5C%5C%5Cf%283%29%3Df%282%2B1%29%20%3D%20%5Cdfrac%7B5%7D%7B2%7D%5Bf%282%29%5D%5C%5C%5C%5Cf%283%29%20%3D%202.5%20%5Ctimes%208%5C%5C%5C%5Cf%283%29%20%3D%2020)
f(4)
![f(x+1) = \dfrac{5}{2}[f(x)]\\\\f(4)=f(3+1) = \dfrac{5}{2}[f(3)]\\\\f(4) = 2.5 \times 20\\\\f(4) = 50](https://tex.z-dn.net/?f=f%28x%2B1%29%20%3D%20%5Cdfrac%7B5%7D%7B2%7D%5Bf%28x%29%5D%5C%5C%5C%5Cf%284%29%3Df%283%2B1%29%20%3D%20%5Cdfrac%7B5%7D%7B2%7D%5Bf%283%29%5D%5C%5C%5C%5Cf%284%29%20%3D%202.5%20%5Ctimes%2020%5C%5C%5C%5Cf%284%29%20%3D%2050)
f(5)
![f(x+1) = \dfrac{5}{2}[f(x)]\\\\f(5)=f(4+1) = \dfrac{5}{2}[f(4)]\\\\f(5) = 2.5 \times 50\\\\f(5) = 125](https://tex.z-dn.net/?f=f%28x%2B1%29%20%3D%20%5Cdfrac%7B5%7D%7B2%7D%5Bf%28x%29%5D%5C%5C%5C%5Cf%285%29%3Df%284%2B1%29%20%3D%20%5Cdfrac%7B5%7D%7B2%7D%5Bf%284%29%5D%5C%5C%5C%5Cf%285%29%20%3D%202.5%20%5Ctimes%2050%5C%5C%5C%5Cf%285%29%20%3D%20125)
Hence, the value of f(5), if f(1) = 3. 2 and f(x+1) = Five-halves(f(x)) is 125.
Learn more about Function:
brainly.com/question/5245372