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ludmilkaskok [199]
3 years ago
7

Lucy has the spinner pictured and

Mathematics
2 answers:
mario62 [17]3 years ago
8 0

Answer:

d

Step-by-step explanation:

STALIN [3.7K]3 years ago
4 0
The answer is 1 out of 3 I think
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Which quadrilateral has two pairs of different but equal adjacent sides?
dem82 [27]
The answer is most likely a 'kite'. If not it would be something very similar.
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Find the area of each figure. Round to the nearest hundredth if needed.
Hitman42 [59]

Answer:

<h3>#1</h3>

<u>Trapezoid</u>

  • A = (b₁ + b₂)h/2
  • A = (4.8 yd + 29.4 ft)(8 yd)/2 = (14.6 yd)(4 yd) = 58.4 yd²
<h3>#2</h3>

<u>Rectangle</u>

  • A = ab
  • A = 2 yd * 3.1 yd = 6.2 yd²
<h3>#3</h3>

<u>Equilateral triangle</u>

  • A = √3/4a²
  • A = √3/4(10²) = 25√3
<h3>#4</h3>

<u>Regular octagon</u>

  • A = aP/2
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6 0
3 years ago
If the maximum acceleration that is tolerable for passengers in a subway train is 1.74 m/s2 and subway stations are located 930
Free_Kalibri [48]
Given that the subway stations are 930 m apart, the train have to be accerelated for half the distance and then decerelated for the rest of the distance.

Recall that the distance travelled by an object with an initial velocity, u, for a period of time, t, at an accereration, a, is given by
s=ut+ \frac{1}{2} at^2

But, we assume that the train accelerates from rest, thus
s=\frac{1}{2} at^2 \\  \\ \Rightarrow465=\frac{1}{2}(1.74)t^2 \\  \\ \Rightarrow t^2=534.48 \\  \\  \Rightarrow t=\sqrt{534.48}=23.12

The maximum speed is attained at half the center of the distance between subway stations (i.e. at distance = 465 m).

Thus, maximum speed = distance / time = 465 / 23.12 = 20.11 m/s.
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3 years ago
What is 0.2 repeated as a fraction?
Elina [12.6K]
0.2 in fraction form is 1/5
8 0
3 years ago
I need help please 36 points
geniusboy [140]

Using the power of zero property, we find that:

a) The simplification of the given expression is 1.

b) Since , equivalent expressions are:  and .

--------------------------------

The power of zero property states that any number that is not zero elevated to zero is 1, that is:

Thus, at item a, , thus the simplification is .

At item b, equivalent expressions are found elevating non-zero numbers to 0, thus  and .

5 0
3 years ago
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