The answer is most likely a 'kite'. If not it would be something very similar.
Answer:
<h3>#1</h3>
<u>Trapezoid</u>
- A = (b₁ + b₂)h/2
- A = (4.8 yd + 29.4 ft)(8 yd)/2 = (14.6 yd)(4 yd) = 58.4 yd²
<h3>#2</h3>
<u>Rectangle</u>
- A = ab
- A = 2 yd * 3.1 yd = 6.2 yd²
<h3>#3</h3>
<u>Equilateral triangle</u>
- A = √3/4a²
- A = √3/4(10²) = 25√3
<h3>#4</h3>
<u>Regular octagon</u>
- A = aP/2
- A = 14.5(12*8)/2 = 696
Given that the subway stations are 930 m apart, the train have to be accerelated for half the distance and then decerelated for the rest of the distance.
Recall that the distance travelled by an object with an initial velocity, u, for a period of time, t, at an accereration, a, is given by

But, we assume that the train accelerates from rest, thus

The maximum speed is attained at half the center of the distance between subway stations (i.e. at distance = 465 m).
Thus, maximum speed = distance / time = 465 / 23.12 = 20.11 m/s.
0.2 in fraction form is 1/5
Using the power of zero property, we find that:
a) The simplification of the given expression is 1.
b) Since , equivalent expressions are: and .
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The power of zero property states that any number that is not zero elevated to zero is 1, that is:
Thus, at item a, , thus the simplification is .
At item b, equivalent expressions are found elevating non-zero numbers to 0, thus and .