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Alla [95]
3 years ago
15

Animals with reproduction dependent on internal fertilization need all of the following except

Chemistry
1 answer:
Elenna [48]3 years ago
6 0
Internal development of embryos.
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During an experiment, Mr. Lehman tells his students to be alert for signs that an endothermic reaction is happening. Which of th
Aliun [14]

A test tube becomes cool to the touch.

Explanation:

The signs for an endothermic reaction would most likely be that a test tube becomes cool to touch. An endothermic reaction is a reaction in which heat is absorbed from the environment.

  • At the end of this heat change, the surrounding becomes colder.
  • Most endothermic reactions are always shown by the test tube becoming colder.
  • For exothermic reaction in which heat is given off to the surroundings, the tube should be hotter.

Learn more:

Exothermic reactions brainly.com/question/10567109

#learnwithBrainly

4 0
3 years ago
Read 2 more answers
Analyzing Characteristics of Outer Planets
Afina-wow [57]

Answer:also confused ?

Explanation:cant see full answer

4 0
3 years ago
When aqueous solutions of Li3PO4 and MgSO4 are mixed, Mg3(PO4)2 is a precipitate
Lesechka [4]

Answer:

Li2SO4

Explanation:

Balance the reaction of Li3PO4 + MgSO4 = Li2SO4 + Mg3(PO4)2 using this chemical equation balancer!

8 0
3 years ago
It takes 53.0 J to raise the temperature of an 11.0 g piece of unknown metal from 13.0∘C to 24.2 ∘
jasenka [17]
You need to use q = mc(delta t) 
<span>Solve for c: </span>

<span>c = q / m(delta t) </span>

<span>q = 55.o J </span>
<span>m = 11.0 g </span>
<span>delta t = 24.5 - 13.0 = 11.5 deg C </span>

<span>c = 55 J / 11.0 g)(11.5 C) </span>
<span>c = 0.435 J/ g C</span>
7 0
3 years ago
One sphere has a radions of 181 cm, another has a radius of 5.01 cm. What is the difference in volume (in cubic centimeters) bet
PSYCHO15rus [73]

Answer:

2.4*10^{7}cm^{3}

Explanation:

First you should calculate the volume of a big sphere,so:

V_{big}=\frac{4}{3}\pi r^{3}

V_{big}=\frac{4}{3}\pi (181cm)^{3}

V_{big}=2.4*10^{7}cm^{3}

Then you calculate the volume of a small spehre, so:

V_{small}=\frac{4}{3}\pi r^{3}

V_{small}=\frac{4}{3}\pi (5.01cm)^{3}

V_{small}=5.3*10^{2}cm^{3}

Finally you subtract the two quantities:

V_{big}-V_{small}=2.4*10^{7}cm^{3}-5.3*10^{2}cm^{3}

V_{big}-V_{small}=2.4*10^{7}cm^{3}

5 0
3 years ago
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