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Vlad [161]
3 years ago
13

Find the mass in grams of 1.00 x 10^23 molecules of N2

Chemistry
1 answer:
Leya [2.2K]3 years ago
5 0

  the mass  in grams  of  1.00 x 10^23  molecules of N2 is 4.648  g


 <u><em>calculation</em></u>

Step  1:  use  the Avogadro's  constant   to determine  the moles of N2

According  to Avogadro's  law    1   mole  =  6.02 x 10 ^23  molecules

                                                       ?  moles  = 1.00 x 10 ^23  molecules


      <em>by  cross  multiplication</em>

 = (1  mole  x 1.00  x10^23  molecules)  / (  6.02  x 10^23  molecules)

        =0.166 moles  of  N2


Step 2 :  find  mass  of N2

Mass =  moles x molar  mass

From  periodic  table the molar  mass  of N2  = 14 x2  = 28 g/mol

mass = 0.166  moles  x   28  g/mol   = 4.648  g


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which is the correct order of ease of carbon dioxide production by heating the group II metal carbonates?​
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Which is the correct order of ease of carbon dioxide production by heating the group II metal carbonates?​

A) BaCO_{3}   > SrCO_{3}  >  CaCO_{3}  > MgCO_{3}

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Explanation:

The correct option is A:

<h2> </h2>

BaCO_{3}   > SrCO_{3}  >  CaCO_{3}  > MgCO_{3}

On the periodic table, carbonates required stronger heating as one does down the groupings in order for them to decompose. The implication is that  the stability of compounds will increase from MgCO_{3} to BaCO_{3} ​.  

 

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