A solution is prepared by adding 1.43 mol of potassium chloride (kcl) to 889 g of water. The concentration of kcl is 1.61 molal.
mol of Kcl (potassium chloride)= 1.43
water = 889 g
the formula for calculating molality is:
molality = moles of solute/kilograms of solvent
1kg = 1000g so, 889g = 0.889kg
m = 1.43/0.889 = 1.61 molal
The answer is
2Ag+(aq) + SO4-2(aq) → Ag2SO4(s)
<span>NO3- and K+ ions are spectators </span>
<span>Food couldn’t reach the stomach without the esophagus and the throat.</span>
The three broad classes of elements are:
Metals
Metalloids
Nonmetals
